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Part A If 55 J of heat is added to an aluminum can with a mass of 22.4 g, what is its temperature change? Specific heat capac
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Answer #1

Given:

Q = 55 J

m = 22.4 g

C = 0.903 J/g.oC

use:

Q = m*C*ΔT

55.0 = 22.4*0.903*ΔT

ΔT = 2.72 oC

Answer: 2.7 oC

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