a 95% confidence interval with a margin of error of 0.03 is desired. previous experience suggests approximately 0.2. the correct formula for the required sample size is:
a 95% confidence interval with a margin of error of 0.03 is desired. previous experience suggests...
To calculate a confidence interval, the margin of error (E) must first be calculated. The Margin of Error, E, for means is: E = 1.96*s/sqrt(n), where s is the sample standard deviation, n is the sample size. The “sqrt” stands for square root. The Margin of Error, E, for proportions is: E = 1.96*sqrt[p*(1-p)/n], where s is the sample standard deviation, n is the sample size, and p is the proportion. Use the Confidence Interval formula above, and the correct...
Find the margin of error for a 95% confidence interval for estimating the population mean when the sample standard deviation equals 92, with a sample size of (a) 400,(b) 1800. What is the effect of the sample size? 2. The margin of error for a 95% confidence interval with a sample size of 400 is (Round to the nearest tenth as needed.) b. The margin of error for a 90% confidence interval with a sample size of 1600 is (Round...
sample should be taken to provide a 95% confidence interval with a margin of error of .05? At 95% confidence, how large a sample should be taken to obtain a margin of error of .03 for the estimation of a population proportion? Assume that past data are not available for developing a planning value for p* 34.
113 The margin of error for the 95% confidence interval of the mean fill is. 2 A 0.48 3 B 0.41 4 C 0.36 5 D 0.32 714 As a class project, each of 280 students taking E270 is required to obtain a sample of n = 100 students and build a B 95% confidence interval for the distance travelled to the campus. The instructor thus receives 280 different interval e estimates. The instructor would expect_ ofthese intervals to capture...
What sample size is needed to obtain a 95% confidence interval whose margin of error is no more than 1.7 for the mean of a normal population with standard deviation 4.5?
Determine the margin of error for a 95% confidence
interval to estimate the population mean when s=37 for the sample
sizes below.
Solve for c) n=46.
htmathe Student Homework Theme =41778etod y FALL 2019 STAT 3309 CRN 120961 Homework: Section 8.3 Confidence intervals with s Homework Score: 0 57 of 1 pt 28.3.22-T Determine the margin of error for a 95% confidence interval to estimate the E a) n. 13 b) n = 30 c) n46 a) The margin of...
It is desired to have a margin of error of 100 with 99% confidence. The population standard deviation is 500. What is the necessary sample size? To reduce the margin of error to 50 what would be the necessary sample size?
Which of the following would produce a confidence interval with a larger margin of error than the 95% confidence interval with a sample size of 50? A. using a sample size of 100 and fix the confidence level. B. using a confidence level of 90% and fix the sample size. C. using a confidence level of 99% and fix the sample size. D. using a sample size of 500 and fix the confidence level. E. None of the above.
Determine the sample size needed in forming a 95% confidence interval for a proportion with margin of error of 0.04. (Use the “safe approach” for the population proportion (i.e., p=.50) Repeat part a.) for a margin of error of 0.02.
Assume that you want to construct a 95% confidence interval estimate of a population mean. Find an estimate of the sample size needed to obtain the specified margin of error for the 95% confidence interval. The sample standard deviation is given below. Margin of error equals$5, standard deviation equals$19 The required sample size is __.