To reduce the margin of error to 50 what would be the necessary sample size?
It is desired to have a margin of error of 100 with 99% confidence. The population...
Determine the margin of error for a 99% confidence interval to estimate the population proportion with a sample proportion equal to 0.90 for the following sample sizes. a. nequals100 b. nequals180 c. nequals260 LOADING... Click the icon to view a portion of the Cumulative Probabilities for the Standard Normal Distribution table. a. The margin of error for a 99% confidence interval to estimate the population proportion with a sample proportion equal to 0.90 and sample size nequals100 is nothing.
a sample size of _ is needed So there a 99% confidence interval will have a margin of error of three.so there a 99% confidence interval will have a margin of error of three. 1. simple random sample of 100 2. mean was 125 hours 3. standard deviation is 20 hours.
Find the margin of error for a 95% confidence interval for estimating the population mean when the sample standard deviation equals 92, with a sample size of (a) 400,(b) 1800. What is the effect of the sample size? 2. The margin of error for a 95% confidence interval with a sample size of 400 is (Round to the nearest tenth as needed.) b. The margin of error for a 90% confidence interval with a sample size of 1600 is (Round...
Which of the following would produce a confidence interval with a larger margin of error than the 95% confidence interval with a sample size of 50? A. using a sample size of 100 and fix the confidence level. B. using a confidence level of 90% and fix the sample size. C. using a confidence level of 99% and fix the sample size. D. using a sample size of 500 and fix the confidence level. E. None of the above.
Use the given margin of error, confidence level, and population standard deviation, sigmaσ, to find the minimum sample size required to estimate an unknown population mean, muμ. Margin of error: 1.91.9 inches, confidence level: 9595%, sigmaσequals=2.62.6 inches A confidence level of 9595% requires a mimimum sample size of nothing. (Round up to the nearest integer.)
what is the margin of error and the confidence interval? Question Help In a random sample of seven people, the mean driving distance to work was 24.7 miles and the standard deviation was 6.6 miles. Assuming the population is normally distributed and using the I-distribution, a 90% confidence interval for the population mean is (15.5, 33.9) (and the margin of error is 9.2). Through research, it has been found that the population standard deviation of driving distances to work is...
What sample size needs to be taken to provide a margin of error of 9 or less with 99% confidence when you have a known population standard deviation of 17?
6. Determine the minimum sample size required to have a margin of error of 2% with 99% confidence. [4p
(C) If the confidence levels were 99.5% rather than 99.9% would the margin of error be larger or smaller than the result in part (a) ? Explain. The margin of error would be ( larger or smaller ) , since ( an increase or a decrease ) in the confidence level will ( decrease or increase ) the critical value z a/2. SAT scores: A college admissions officer takes a simple random sample of 100 entering freshmen and computes their...
To calculate a confidence interval, the margin of error (E) must first be calculated. The Margin of Error, E, for means is: E = 1.96*s/sqrt(n), where s is the sample standard deviation, n is the sample size. The “sqrt” stands for square root. The Margin of Error, E, for proportions is: E = 1.96*sqrt[p*(1-p)/n], where s is the sample standard deviation, n is the sample size, and p is the proportion. Use the Confidence Interval formula above, and the correct...