Solution :
Given that,
= 0.5
1 - = 1 - 0.5 = 0.5
margin of error = E = 2% = 0.02
At 99% confidence level the z is,
= 1 - 99%
= 1 - 0.99 = 0.01
/2 = 0.005
Z/2 = 2.576
Sample size = n =
(Z/2 / E)2 *
* (1 -
)
= (2.576 / 0.02)2 * 0.5 * 0.5
=4147.36
Sample size = 4148
6. Determine the minimum sample size required to have a margin of error of 2% with 99% confidence. [4p
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1. Given n=2500 and p=0.86, find the margin of error E that
corresponds to a 99% confidence level
2. you are given a margin of error as three percentage points
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