1)Margin of error E= z × sqrt( p (1-p)/n )
We have given population proportion and sample values let find z value from z table in 2 tail at 99% confidence.
2) sample n= (Z/E)^2 (p' (1-p'))
Given E and p values and find z value from z table at 99% confidence in 2 tail.
And always round the sample value to the next highest value
1. Given n=2500 and p=0.86, find the margin of error E that corresponds to a 99%...
(ipom) 1. Given n-2500 and β 0.86, find the margin of error E that corresponds to a 99% confidence level o 0.014 0 0.048 0 0.018 0.007 2. You are given a margin of error as 3 percentage points and a confidence level of 99%. Ifthe sample percentage from a recent poll is 35%, find the minimum sample size to estimate a (1 point) population proportion. 496 e 2579 1677 248
you are given a margin of error as 3 percentage points and a confidence level of 99%. if the sample percentage from a recent poll is 35% find the minimum sample size to estimate a population proportion. 496 1677 248 2579
Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level. Round the margin of error to four decimal places. In a clinical test with 1600 subjects, 800 showed improvement from the treatment. Find the margin of error for the 99% confidence interval used to estimate the population proportion. a. 0.0322 b. 0.0184 c. 0.0245 d. 0.0282 ON
Assume that a sample is used to estimate a population proportion p. Find the margin of error M.E. that corresponds to a sample of size 384 with 87% successes at a confidence level of 99.5%. M.E. = % Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places. Round final answer to one decimal place A political candidate has asked you to conduct a poll to determine what percentage of people...
Assume that a sample is used to estimate a population proportion p. Find the margin of error M.E. that corresponds to a sample of size 259 with 74.9% successes at a confidence level of 99%. M.E. = % Report answer accurate to one decimal place (as a number of percentage points). Answer should be obtained without any preliminary rounding (however, the critical value may be rounded to 3 decimal places).
given n = 875 and p = 0.45 find the margin of error E that corresponds to a 95% confidence level. .001 .033 .044 .016
Assume that a sample size is used to estimate a population proportion p. Find the margin of error E that corresponds to the following statistics and confidence level. Round the margin of error to 4 decimal places. 95% confidence, n = 9000, of which 35% are successes. Use a TI84 and show all of your work
Determine the margin of error for a 99% confidence interval to estimate the population proportion with a sample proportion equal to 0.90 for the following sample sizes. a. nequals100 b. nequals180 c. nequals260 LOADING... Click the icon to view a portion of the Cumulative Probabilities for the Standard Normal Distribution table. a. The margin of error for a 99% confidence interval to estimate the population proportion with a sample proportion equal to 0.90 and sample size nequals100 is nothing.
Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level. Round the margin of error to four decimal places. bing bing ocene 99% confidence; n = 5900, x = 1770 000 a. 0.00878 b. 0.0117 c. 0.0135 d. 0.0154
Use the given data to find the minimum sample size required to estimate the population proportion. Margin of error: 0.089; confidence level: 99%; and unknown sample proportion p^