(a) Determine the electric potential at distances 1.0 cm, 2.0 cm, and 3.0 cm from a...
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(a) Determine the electric potential at distances 1.0 cm, 2.0 cm, and 3.0 cm from a point charge of +5.0
nC. (b) How much potential energy would a +10.0 nC charge have if it is placed 3.0 cm from the +5.0 nC charge? (c) Determine the potential difference from a distance of 1.0 cm to a distance of 3.0 cm from a point charge of - 5.0 nC. (a. 4500 V, 2250 V, 1500 V, b. 15 μJ, c. 3000 V)
Homework Answers
Concept - use the definition of potential and
potential energy to find the solutions as shown below
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(a) Determine the electric potential at distances 1.0 cm, 2.0
cm, and 3.0 cm from a...
Two point charges 2.0 cm apart have an electric potential energy -450 μJ . The total...
Two point charges 2.0 cm apart have an electric potential energy -450 μJ . The total charge is 30 nC . What is the lesser charge? What is the larger charge?
(a) Find the electric potential energy of the -5.0nc point charge. (b) How much work would...
(a) Find the electric potential energy of the -5.0nc point
charge. (b) How much work would it take to move the 5.0nc point
charge to infinity?
-7.5 ncO 2.0 cm 10.0 nc - 5.0 nc 3.0 cm
Part A Review What is the electric potential at the point (1.0 cm, 2.0 cm)? A...
Part A Review What is the electric potential at the point (1.0 cm, 2.0 cm)? A given system has the equipotential surfaces shown in (Figure 1). Express your answer to three significant figures and include appropriate units. Value Units Submit Figure < 1of1 Incorrect: Try Again; 5 attempts remaining Enter your answer using units of electric potential. y (Cm) Part B How much work is done by the electric force when a 0.40-C charge is moved from the point (1.0...
Q1) A spherical conductor (radius = 1.0 cm) with a charge of 2.0 pC is within...
Q1) A spherical conductor (radius = 1.0 cm) with a charge of 2.0 pC is within a concentric hollow spherical conductor (inner radius = 3.0 cm, outer radius = 4.0 cm) which has a total charge of -3.0 pC. What is the magnitude of the electric field 2.0 cm from the center of these conductors. Q2)A charge is uniformly distributed along the entire x-axis. If each 20 cm length of the x-axis carries 2.0 nC of charge. What is the...
A charge of 10.0 pC is distributed uniformly on a spherical surface (radius = 2.0 cm),...
A charge of 10.0 pC is distributed uniformly on a spherical surface (radius = 2.0 cm), and a second point charge of -10.0 PC is located at the center of the sphere. Determine the magnitude of the electric field a) 5.0 cm from the center of the sphere. b) 1.0 cm from the center of the sphere. c) What is the potential difference between two points mentioned in parts (a) and (b)?
A 1.0 nC charge is placed at (0.0 cm, 2.0 cm) and another 1.0 nC charge...
A 1.0 nC charge is placed at (0.0 cm, 2.0 cm) and another 1.0 nC charge is placed at (0 cm,-2.0 cm). A third charge +q is placed along a line halfway between q1 and q2 such that the angle between the forces on q due to each of the other two charges is 60∘. The resultant force on q is (5.0 × 10^-5i) N. What is the magnitude of the charge q?
a) A 3.0 nC charge is located at (0,0). A second charge of 2.0 nC is...
a) A 3.0 nC charge is located at (0,0). A second charge of 2.0 nC is located at x = 5.0 m. At a point P on the y-axis determine the electric potential due to the other two charges. You are free to choose the location of this point along the y-axis. b) How much work is required to bring a third charge from infinity to this point P? You are free to choose the value of this third charge....
Specify the Electric Field Strengths at different distances?
A 10-cm-long thin glass rod uniformly charged to 5.00 nC and a 10-cm-long thin plastic rod uniformly charged to - 5.00 nC are placed side by side, 4.00 cm apart. Whatare the electric field strengths to at distances 1.0 cm, 2.0 cm, and 3.0 cm from the glass rod along the line connecting the midpoints of the two rods?E1:E2:E3:
Two point charges are placed as shown in the figure. 3.0 cm -------- 3.0 nC -4.0...
Two point charges are placed as shown in the figure. 3.0 cm -------- 3.0 nC -4.0 nC (a) At one point to the left of the - 4.0 nC charge, the electric field is zero. How far to the left of the -4.0 nC charge is this point? (b) At one point to the left of the -4.0 nC charge, the electric potential is zero. How far to the left of the - 4.0 nC charge is this point? (c)...
What is the potential difference ΔVAB? What is the potential difference ΔVBC? 2.0 cm 1.0 cm...
What is the potential difference ΔVAB?
What is the potential difference ΔVBC?
2.0 cm 1.0 cm 2.0 nC/ с .
(a) Find the electric potential energy of the -5.0nc point
charge. (b) How much work would it take to move the 5.0nc point
charge to infinity?
-7.5 ncO 2.0 cm 10.0 nc - 5.0 nc 3.0 cm
Part A Review What is the electric potential at the point (1.0 cm, 2.0 cm)? A given system has the equipotential surfaces shown in (Figure 1). Express your answer to three significant figures and include appropriate units. Value Units Submit Figure < 1of1 Incorrect: Try Again; 5 attempts remaining Enter your answer using units of electric potential. y (Cm) Part B How much work is done by the electric force when a 0.40-C charge is moved from the point (1.0...
A charge of 10.0 pC is distributed uniformly on a spherical surface (radius = 2.0 cm), and a second point charge of -10.0 PC is located at the center of the sphere. Determine the magnitude of the electric field a) 5.0 cm from the center of the sphere. b) 1.0 cm from the center of the sphere. c) What is the potential difference between two points mentioned in parts (a) and (b)?
Two point charges are placed as shown in the figure. 3.0 cm -------- 3.0 nC -4.0 nC (a) At one point to the left of the - 4.0 nC charge, the electric field is zero. How far to the left of the -4.0 nC charge is this point? (b) At one point to the left of the -4.0 nC charge, the electric potential is zero. How far to the left of the - 4.0 nC charge is this point? (c)...
What is the potential difference ΔVAB?
What is the potential difference ΔVBC?
2.0 cm 1.0 cm 2.0 nC/ с .
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