ZuoTi.Pro
Question

A 4.50 g mass of solid Al2(SO4)3 is added in enough water to make 125 mL...

  1. A 4.50 g mass of solid Al2(SO4)3 is added in enough water to make 125 mL of solution. What is the molarity of Al3+ ions in the final solution?

science   chemistry   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

molar mass of Al2(SO4)3 = 342.15g/mole

mass of Al2(SO4)3   = 4.50g

volume of solution = 125ml

molarity   = mass of Al2(SO4)3*1000/gram molar mass of Al2(SO4)3* volume of solution in ml

               = 4.5*1000/(342.15*125)

                = 0.1052M

Al2(SO4)3 (aq) ---------------> 2Al^3+ (aq) + 2SO4^2-(aq)

0.1052M    --------------------   2*0.1052M

molarity of Al^3+   = 0.2104M

0 0
Add a comment
Know the answer?
Add Answer to:
A 4.50 g mass of solid Al2(SO4)3 is added in enough water to make 125 mL...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • a) How many mol of Al2(SO4)3 are required to make 40 mL of a  0.050 M Al2(SO4)3...

    a) How many mol of Al2(SO4)3 are required to make 40 mL of a  0.050 M Al2(SO4)3 solution? (Hint, molarity is moles per liter. You know the molarity. You are given the number of mL's, which can be converted to liters. Just set it up so the units cancel and you get "moles".) moles Al2(SO4)3 b) What is the molecular weight of Al2(SO4)3, to the nearest gram? c) What mass of Al2(SO4)3 is required to make 40 mL of a  0.050 M...

  • a) How many moles of Al2(SO4)3 are required to make 55 mL of a 0.050 M...

    a) How many moles of Al2(SO4)3 are required to make 55 mL of a 0.050 M Al2(SO4)3 solution? (Hint, molarity is moles per liter. You know the molarity. You are given the number of mL's, which can be converted to liters. Just set it up so the units cancel and you get "moles".) moles Al2(SO4)3 b) What is the molecular weight of Al2(SO4)3, to the nearest gram? grams c) What mass of Al2(SO4)3 is required to make 55 mL of...

  • a) How many moles of Al2(SO4)3 are required to make 44 mL of a 0.090 M Al2(SO4)3 solution? (Hint, molarity is moles per...

    a) How many moles of Al2(SO4)3 are required to make 44 mL of a 0.090 M Al2(SO4)3 solution? (Hint, molarity is moles per liter. You know the molarity. You are given the number of mL's, which can be converted to liters. Just set it up so the units cancel and you get "moles".) moles Al2(SO4)3 b) What is the molecular weight of Al2(SO4)3, to the nearest gram? grams c) What mass of Al2(SO4)3 is required to make 44 mL of...

  • 5.0 g of solid Al(NO3)3 was added to enough water to make a 100.0 mL solution....

    5.0 g of solid Al(NO3)3 was added to enough water to make a 100.0 mL solution. Al(NO3)3 is very soluble in water. 1. Write out the dissolution reaction that occurs when the solid Al(NO3)3 was added to water. 2. What is the concentration, in Molarity, of Al(NO3)3 once it is dissolved in the water? 3. If 53 mL of water was added to the original Al(NO3)3 solution described above, what is the new concentration in Molarity? 4. What is the...

  • a) How many moles of Al2(SO4)3 are required to make 43 mL of a 0.060 M...

    a) How many moles of Al2(SO4)3 are required to make 43 mL of a 0.060 M Al2(So4)3 solution? (Hint, molarity is moles per liter. You know the molarity. You are given the number of mL's, which can be converted to liters. Just set it up so the units cancel and you get "moles".) moles Al2(SO4)3 b) What is the molecular weight of Al2(S04)3, to the nearest gram? grams c) What mass of Al2(SO4)3 is required to make 43 mL of...

  • A solution is made by dissolving 26.3 g of chromium(III) sulfate, Cr2(SO4)3, in enough water to...

    A solution is made by dissolving 26.3 g of chromium(III) sulfate, Cr2(SO4)3, in enough water to make exactly 500 mL of solution. Calculate the concentration (molarity) of Cr2(SO4)3 in mol/L (M). M Cr2(SO4)3

  • 3. Consider a solution prepared by dissolving 30.000 g of BaCl, in enough water to make a 200 ml solution. a. Deter...

    3. Consider a solution prepared by dissolving 30.000 g of BaCl, in enough water to make a 200 ml solution. a. Determine the molarity of the BaCl, solution. b. Determine the molarity of Ba? ions. c. Determine the molarity of Clions. A chemist adds 800 mL of a 0.140 M NaCl solution to the existing 200 ml solution. d. Determine the new total volume of solution. e. Determine the new molarity of Baltions. f. Determine the new molarity of Ci...

  • 3. Consider a solution prepared by dissolving 30.000 g of BaCl, in enough water to make...

    3. Consider a solution prepared by dissolving 30.000 g of BaCl, in enough water to make a 200 ml solution. a. Determine the molarity of the BaCl, solution. b. Determine the molarity of Ba2+ ions. c. Determine the molarity of Chions. A chemist adds 800 mL of a 0.140 M NaCl solution to the existing 200 mL solution. d. Determine the new total volume of solution. e. Determine the new molarity of Ba2+ ions. f. Determine the new molarity of...

  • 40.0mL of 0.270M Ba(OH)2 was mixed with 2.0 mL of 0.33M Al2(SO4)3. Each product was insoluable...

    40.0mL of 0.270M Ba(OH)2 was mixed with 2.0 mL of 0.33M Al2(SO4)3. Each product was insoluable in water-2 precipitates form! Calculate the mass of the precipitate, and the molarities of the ions remaining in the solution.

  • Question 25 of 35 > What is molarity of A1+ ions in a solution prepared by...

    Question 25 of 35 > What is molarity of A1+ ions in a solution prepared by dissolving 1.06 g of Al2(SO4)3 in 250,0 mL of water. Molar mass of Al2(SO4)3 is 342.15 g/mol. Enter your answer in the provided box. For this question, show your complete work in Part 2 Question 24 of 35 > An aqueous potassium iodate stock solution is made by dissolving 5.86 mol KIO, in sufficient water for the final volume of the solution to be...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT