Question

Homework Question

Write a void function called transformArray that takes two parameters - a reference to a pointer to a dynamically allocated array of ints, and the size of that array.  The pointer is passed by referencebecause you want to change the value of the pointer. The function should dynamically allocate an array that is twice as long, filled with the values from the original array followed by each of those values times 2. For example, if the array that was passed in was {4, 2, 5}, then it should be replaced by {4, 2, 5, 8, 4, 10}. The address of the new array should be assigned to the pointer that was passed as a parameter.  The function should prevent any memory leaks. Remember to also prevent memory leaks in the main you use for testing.

For example, it could be used like this:

   int* myArray = new int[3];
   myArray[0] = 4;
   myArray[1] = 2;
   myArray[2] = 5;

   transformArray(myArray, 3);

   for (int i=0; i<6; i++)
      cout << myArray[i] << endl;

   delete []myArray;

The file must be named transformArray.cpp.

Answer 1

code:

#include <iostream>

using namespace std;

int * transformArray(int* p, int size){

//creating solution array with double size

int* mySol = new int[size*2];

int i=0;

//storing original array values to solution array

while(i<size){

mySol[i] = p[i];

i++;

}

int temp=0;

//the remaining half of solution array will be double of

//values of the array passed

while(i<2*size){

mySol[i] = p[temp]*2;

temp++;

i++;

}

//changing the pointer

p = mySol;

//return the pointer

return p;

//delete solution array

delete []mySol;

}

int main() {

int* myArray = new int[3];

myArray[0] = 4;

myArray[1] = 2;

myArray[2] = 5;

myArray = transformArray(myArray, 3);

for (int i=0; i<6; i++)

cout << myArray[i] << endl;

delete []myArray;

}