1-. Why does the term ‘anode’ and ‘cathode’ not apply to a DIAC?
2-Why are TRIACs not used in DC circuits?
1-. Why does the term ‘anode’ and ‘cathode’ not apply to a DIAC? 2-Why are TRIACs...
2. a. Identify the anode and cathode for the cell reactions below as they are written. Then determine the standard cell potential (Eiseu) for each. Reaction Cathode Anode Essel Agt(aq) + Li(s) → Ag(s) + Litlaq) 2 Cr(s)_+ 3 Snº+(aq) 3 Sn2+(aq) + 2 Cr3+(ag) Zn(s) + Fe2+lag) ► Fe(s) + Zn2+(aq) b. Which of the reactions above are spontaneous? 3. Rank the species below in terms of oxidizing strength. (1 = strongest oxidizer, 6 = weakest) Fe3+ Cu2+ F2...
After electroplating, why do you need to wash the copper anode and cathode with distilled water and acetone before weighing them? what would happen if you didn't do this step before weighing them?
need help !! with questions 2,4,5,6
Initial Mass of Cathode electrode (Fe) Initial Mass of Anode electrode (Zn) Final Mass of Cathode 10.0g 10, og 10,209 .2g Fe 3+ (aq)+32 z Fecs) Mass of Zinc deposited on cathode (g) Half reaction in Cathode Half reaction in Anode Zn(s) Eszn²+ (aq) + Ze Za(s) + 2 Fest (1) ► 2* (g) +2 Fe²+ (aq) Overall Cell Reaction Standard Cell Potential, Ecellº .440 +.763 3.32 3 (Eºcell = Ecathode - Eanode) Number...
1. Identify the anode, the cathode, the reduced species and the oxidized species for the following electrochemical cells. Write the half reactions for the anode and cathode, the overall reaction. Calculate the total cell potential. a) Fe (8)| Fe (aq) (0.2 M) || Ni” (aq) (0.1 M) | Ni(s) b) Zn (s) | Zn? (aq) (1.0 x 10' M)||Cl(aq)(0.3 M) CI, (g) (0.100 bar) Pt (S) c) Pb (s) Pb2(aq) (1.0 x 10ʻM) || Cu (aq) (1.0 x 10M) Cu...
Draw a labelled diagram of the apparatus that includes the anode, the cathode, the electrolyte, the direction of ion flow and the direction of electron flow provided by the power source. 28. Answer (4 Marks) Cu 29. Write and identify the half-reactions and net reaction. Answer (3 Marks) Cathode Half-Reaction Anode Half-Reaction Net Reaction 30. Calculate the theoretical potential difference of this cell. Answer (2 Mark) Chemistry so Unit C Module 6 S Besides deposition of Cu(s), what other empirical...
need a little help with number 3
2. Write both cathode and anode reactions for the following cell reactions: Zn(s)[ZnCl2(aq)||Ci-(aq)|C12(1) Cu(s)/Cu(NO3)2(aq)||Fe(NO3)2(aq)|Fe(s) 3. Find Eº, AG, and K for the above reactions.
Question 1: An ideal diode turns on for positive anode-cathode voltages. But the characteristic of diode does not appear to show any ID values when voltage across the diode is greater than zero (VD > 0). How do you explain this plot? ---Reverse bias Forward bias --- Question 2: Plot (I-V) characteristic if we place a 10 12 resistor in series with the diode? Question 3: Plot (I-V) characteristic if we place a lV voltage source in series with the...
Question 2 1 pts A voltaic cell consists of a Zn/Zn2+ anode and a Ni/Ni2+ cathode at 25°C. The initial concentrations of Ni2+ and Zn2+ are 1.700 M and 0.120 M, respectively. The volume of half-cells is the same. What is the concentration of Ni2+ when the cell potential falls to 0.443V? Enter your answer to 4 decimal places and in units of mM.
A voltaic cell consists of a
Zn/Zn2+ anode and a Ni/Ni2+ cathode at 25
∘C. The initial concentrations of Ni2+ and
Zn2+ are 1.700 M and 0.120 M , respectively. The volume
of half-cells is the same.
Question 2 1 pts A voltaic cell consists of a Zn/Zn2+ anode and a Ni/Ni2+ cathode at 25°C. The initial concentrations of Ni2+ and Zn2+ are 1.700 M and 0.120 M, respectively. The volume of half-cells is the same. What is the concentration...
A voltaic cell is made with a salt bridge of NaNO3 and Fe(NO3)2 for the anode cell and AgNO3 for the cathode cell. a. When constructing the cell, what impact odes the volume of solution in each of the beakers have on the cell potential? b. If you were to add deionized water to the solution that contains Ag+(aq), would this have any effect on the cell voltage? If so, Explain how the cell voltage would change and why. c....