Starting from s = 0 with no initial velocity, a particle is given an acceleration a(v) = 0.13(v2+13)1/2, where a and v are expressed in m/s2 and m/s, respectively. Determine the position of the particle when v= 2 m/s,
Starting from s = 0 with no initial velocity, a particle is given an acceleration a(v)...
QUESTION 3 Starting from so with no initial velocity, a particle is given an acceleration av) - 0.24(v2-24)1/2, where a and vare expressed in m/s2 and m/s, respectively. Determine the position of the particle when y= 4.5 m/s QUESTION 4 Knowing that at the instant shown block Bhas a velocity of 2 m/s to the right and an acceleration of 3 m/s2 to the left, determine (a) the velocity of block A. (b) the acceleration of block A 6m/52 (to...
The velocity of a particle moving along a straight line is given by v = 0.2s1/2 m/s where the position s is in meters. At t = 0 the particle has a velocity v0 = 3 m/s. Determine the time when the particle’s velocity reaches 15 m/s and the corresponding acceleration. Ans: 600 s, a = 0.02 m/s2
The acceleration function (in m/s2) and the initial velocity are given for a particle moving along a line. a(t) t 4 5, 0sts 10 v(0) (a) Find the velocity at time t. 2 4t5 2 v(t) m/s (b) Find the distance traveled during the given time interval. 416.6 Need Help? Talk to a Tutor Read It Watch It The acceleration function (in m/s2) and the initial velocity are given for a particle moving along a line. a(t) t 4 5,...
The acceleration of a particle is given by a = 12(10 – s)-2 m/s2 where s is in meters as it moves along a straight line. If the particle’s initial velocity is v0 = 4 m/s and its initial position is s0 = 2 m, determine the velocity of the particle at s = 8 m. Ans: 5 m/s
The acceleration function (in m/s2) and the initial velocity v(o) are given for a particle moving along a line. a(t) = 2t + 2, VO) = -15, Osts 5 (a) Find the velocity at time t. v(t) = m/s (b) Find the distance traveled during the given time interval.
A particle is travelling along a 1D axis (s-axis) and it's velocity is given as a function of time as, v(t) 3t2-5 in m/s. The initial position of the particle is so 10 m, at time t 0 seconds a) Derive expressions for acceleration, a(t), and position, s(t), using the integral/derivative relationships for acceleration, velocity, and position as functions of time. b) Using your formulas from part a, calculate the velocity, acceleration, and position of the particle for every 1...
A particle starts from the origin at t = 0 with an initial velocity of 5.5 m/s along the positive x axis.If the acceleration is (-2.9 i^ + 4.7 j^)m/s2, determine (a)the velocity and (b)position of the particle at the moment it reaches its maximum x coordinate
The acceleration of a particle as it moves along a straight line is given by a=(2t−1) m/s2, where t is in seconds. Suppose that s = 4 m and v = 8 m/s when t = 0. a)Determine the particle's velocity when t = 4 s . b)Determine the particle's position when t = 4 s c)Determine the total distance the particle travels during the 4-s time period.
A particle starts from the origin at t = 0 with an initial velocity of 5.0 m/s along the positive x axis. If the acceleration is (–3.0i + 4.5j) m/s^2, determine the velocity and position of the particle at the moment it reaches its maximum x coordinate. Can someone explain why when the particle reaches it maximum x coordinate?
Find the position vector for a particle with acceleration, initial velocity, and initial position given below. a(t) = (2+, 4 sin(t), cos(5t)) v(0) = (-3, -5,0) 7(0) = (-5,2, - 1) F(t)