In a random sample of
81
audited estate tax returns, it was determined that the mean amount of additional tax owed was
$3409
with a standard deviation of
$2533.
Construct and interpret a 90% confidence interval for the mean additional amount of tax owed for estate tax returns.
Solution :
Given that,
= 3409
s = 2533
n = 81
Degrees of freedom = df = n - 1 = 81 - 1 = 80
At 90% confidence level the t is ,
= 1 - 90% = 1 - 0.90 = 0.10
/ 2 = 0.10 / 2 = 0.05
t /2,df = t0.05,80 = 1.664
Margin of error = E = t/2,df * (s /n)
= 1.664 * (2533 / 81)
= 468.3
Margin of error = 468.3
The 90% confidence interval estimate of the population mean is,
- E < < + E
3409 - 468.3 < < 3409 + 468.3
2940.7 < < 3877.3
(2940.7, 3877.3 )
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