The following measurements were made using a simple pendulum. L= 946 ± 1mm (The distance from the point of suspension to the centre of mass of the bob), 10T = 19.51 ± 0.05s (the time for 10 periods).
Calculate:
(a) The time and uncertainty of 1 period [ T = …… ± …… s]
(b) The relative uncertainty of the period [ΔT/T = …….]
(c) The relative uncertainty of the length [ΔL/ L = ……… ]
(d) The relative uncertainty of the acceleration due to gravity [ Δg/g = ……….. ]
(e) Δg = …………
(f) The acceleration due to gravity
( g = 4 π2L/T2) and the uncertainty (Δg). Give the answer as (g ± Δg).
The following measurements were made using a simple pendulum. L= 946 ± 1mm (The distance from...
The period T of a simple pendulum with small oscillations is calculated from the formula T=2pi sqrt(L/g) where L is the length of the pendulum and g is the acceleration due to gravity. suppose that measured values of L and g have errors and are corrected with new values where L is increased from 4m to 4.5m and g is increased from 9 m/s2 to 9.8 m/s2. Use differentials to estimate the change in the period. Does the period increase...
The period T of a simple pendulum is given by T=2πLg−−√T=2πLg where L is the length of the pendulum and g is the acceleration due to gravity. Assume that g = 9.80 m/s2 exactly, and that L, in meters, is lognormal with parameters μL = 0.8 and σ2L=0.05.σL2=0.05. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Find P(T > 3).
THE SIMPLE PENDULUM Pre-Lab 1. State the objectives of this experiment. 2. How do you measure the length of a simple pendulum? 3. Define period of a simple pendulum in words. 4. The period of a simple pendulum is related to its length and the acceleration of gravity in an equation. Write down that equation. 5. What is the amplitude of a simple pendulum? 6. What does the period of a simple pendulum depend on? 7. True or false The...
An expression for the period of a simple pendulum with string length ℓ derived using calculus is T = 2(pi)sqrt{ ℓ /g } . Where g is the acceleration due to gravity. Use the data in the table to decide whether or not the pendulum in the experiment can be considered a simple pendulum. Explain your decision. Suppose have the ability to vary the mass m of the bob and the length f of the string. You decide to to...
A simple pendulum consists of a ball of mass M hanging from a uniform string of mass m and length L, with m << M. (a) If the period of oscillations for the pendulum is T, derive an expression for the speed of a transverse wave in the string when the pendulum hangs at rest in terms of m, M, T and g (the acceleration due to gravity). Your expression should not include L. (b) If the string is made...
yBLEMS FOR TOPIC 3 ASSIGNMENT QUESTIONS AND PROBLEMS FOR TOPIC 3.1 A student was supplied with a stop watch, two metre rules and a simole pendulum suspended from a ceiling and was asked to measure the heihple the ceiling indirectly. He set the pendulum swinging through a small angle and measured the period of oscillation for different lengths of the Since he was unable to measure the length of the pendulum direer measured the height of the centre of the...
i would like help to write a program to run the following application in visual studio C++, CLR empty project Borough of Manhatan Community College The City University of New York SCIENCE DEPARTMENT Laboratory Experiment ACCELERATION DUE TO GRAVITY USING A SIMPLE PENDULUM To calculate the value of the acceleration due to gravity by measuring the period of a pendulum with four different lengths. Apparatus Drilled steel ball, string, clamp, support to hold pendulum apparatus, meter stick, and timer Theory:...
T = 4V The figure shows a pendulum with length L that makes a maximum angle @o with the vertical. Using Newton's Second Law, it can be shown that the period T (the time for one complete swing) is given by -TT/2 dx L go 1 - k2 sin2(x) where k = sin(100) and g is the acceleration due to gravity. If L = 2 m and 60 = 46°, use Simpson's Rule with n = 10 to find the...
The figure shows a pendulum with length L that makes a maximum angle oo with the vertical. Using Newton's Second Law, it can be shown that the period T (the time for one complete swing) is given by T = 4 7,6" sin(100) dx 1 - k2 sin2(x) where k = sin and g is the acceleration due to gravity. If L = 5 m and 0. = 46°, use Simpson's Rule with n = 10 to find the period....
(1 point) Suppose a pendulum of length L meters makes an angle of θ radians with the vertical, as n the figure t can be shown that as a function of time, θ satisfies the differential equation d20 + sin θ-0, 9.8 m/s2 is the acceleration due to gravity For θ near zero we can use the linear approximation sine where g to get a linear di erential equa on d20 9 0 dt2 L Use the linear differential equation...