The period T of a simple pendulum with small oscillations is calculated from the formula T=2pi sqrt(L/g) where L is the length of the pendulum and g is the acceleration due to gravity. suppose that measured values of L and g have errors and are corrected with new values where L is increased from 4m to 4.5m and g is increased from 9 m/s2 to 9.8 m/s2. Use differentials to estimate the change in the period. Does the period increase or decrease?
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The period T of a simple pendulum with small oscillations is calculated from the formula T=2pi sqrt(L/g) where L is the...
The period T of a simple pendulum is given by T=2πLg−−√T=2πLg where L is the length of the pendulum and g is the acceleration due to gravity. Assume that g = 9.80 m/s2 exactly, and that L, in meters, is lognormal with parameters μL = 0.8 and σ2L=0.05.σL2=0.05. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Find P(T > 3).
Calculus question please help <3 . (ignore the working) 4. The period of a pendulum is given by T = 2 π l-where l is the length of the pendulum and g is the acceleration due to gravity. Suppose I = 5 feet feet with a maximum error of 0.01 feet .01 feet and T = 2 seconds with a maximum error of 0. 05 seconds Use differentials to estimate the maximum error of g Hint: solve for g first....
A simple pendulum makes 107 complete oscillations in 2.60 min at a location where g = 9.80 m/s2. (a) Find the period of the pendulum. s (b) Find the length of the pendulum. m
1. How much is the period of 1=1.00 m long pendulum on the Moon (g = 1.600 m/s2) 4.97 sec. 2. On a planet X pendulum of the length 0.500 m makes 50.0 oscillations in 1.00 min. Find the acceleration of gravity on the planet X. g = 13.7 m/s2. 3. Find the period of small oscillations of a meter stick suspended by its end near Earth surface (assume g=9.800 m/s2). Notice that this is not a simple pendulum but...
A simple pendulum makes 117 complete oscillations in 3.10 min at a location where g = 9.80 m/s2. (a) Find the period of the pendulum. 1.59 s (b) Find the length of the pendulum. m
A simple pendulum is 2.00 m long. (a) What is the period of small oscillations for this pendulum if it is located in an elevator accelerating upward at 6.00 m/s2? s (b) What is the period of small oscillations for this pendulum if it is located in an elevator accelerating downward at 6.00 m/s2? s (c) What is the period of this pendulum if it is placed in a truck that is accelerating horizontally at 6.00 m/s2? please answer this...
A simple pendulum makes 120 complete oscillations in 2.80 min at a location where g = 9.80 m/s2. (a) Find the period of the pendulum. _________s (b) Find the length of the pendulum. _________m
A simple pendulum is 4.80 m long. (a) What is the period of small oscillations of this pendulum if it is placed in an airplane moving at a constant velocity of 204 m/s at an angle of 52 degrees above the horizontal? (b) What is its period if it is located in an elevator accelerating upward at 8.10 m/s2? (c) What is the period of this pendulum if it is placed in a truck that is accelerating horizontally at 8.10...
The period of a simple pendulum of length L feet is given by: T=2pi(sqrt(L/g))seconds. It is assumed that g, the acceleration due to gravity on the surface of theearth, is 32 feet per second per second. If the pendulum is a clock that keeps good time when L=4 feet, how much time will the clock gain in 24 hours if the length ofthe pendulum is decreased to 3.97 feet? (Use differentials and evaluate the necessary derivative at L=4 feet.) Answer...
A simple pendulum of length ℓ has oscillations described by θ(t) = θm sin(ωt) where ω is the usual angular frequency for a simple pendulum. What will be the angular acceleration of the pendulum at t = T 10 where T is the period of the pendulum