A simple pendulum makes 107 complete oscillations in 2.60 min at a location where g = 9.80 m/s2.
(a) Find the period of the pendulum.
s
(b) Find the length of the pendulum.
m
Solution::
The frequency of the pendulum is f = 107sc/min = 2.60/s
The free fall acceleration g = 9.8 m/s^2
a)
Period of the pendulum is
T = 1/f = 1/2.60= 0.38 s
b)
The period os a simple pendulum is given by
T= 2(pi) sqrt(L/g)
0.38= 2*3.14 *sqrt(L/9.8)
L = 0.036 m
A simple pendulum makes 107 complete oscillations in 2.60 min at a location where g =...
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