Calculus question please help
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Calculus question please help <3 . (ignore the working) 4. The period of a pendulum is given by T = 2 π l-where l is the length of the pendulum and g is the acceleration due to gravity. Suppose I =...
The period T of a simple pendulum with small oscillations is calculated from the formula T=2pi sqrt(L/g) where L is the...
The period T of a simple pendulum with small oscillations is calculated from the formula T=2pi sqrt(L/g) where L is the length of the pendulum and g is the acceleration due to gravity. suppose that measured values of L and g have errors and are corrected with new values where L is increased from 4m to 4.5m and g is increased from 9 m/s2 to 9.8 m/s2. Use differentials to estimate the change in the period. Does the period increase...
Calculus Pendulum Problem(PLEASE HELP) uses differentials and derivatives
The period of a simple pendulum of length L feet is given by: T=2pi(sqrt(L/g))seconds. It is assumed that g, the acceleration due to gravity on the surface of theearth, is 32 feet per second per second. If the pendulum is a clock that keeps good time when L=4 feet, how much time will the clock gain in 24 hours if the length ofthe pendulum is decreased to 3.97 feet? (Use differentials and evaluate the necessary derivative at L=4 feet.) Answer...
This is beyond me right now... 4. Extra Creait: 10 pts The period of a pendulum with length L that makes a maximum angle of 690 with the vertical is dx T/2 1-k2 sin (x) where k =sin (160) and g is...
This is beyond me right now...
4. Extra Creait: 10 pts The period of a pendulum with length L that makes a maximum angle of 690 with the vertical is dx T/2 1-k2 sin (x) where k =sin (160) and g is the acceleration due to gravity. Expand the integrand as a binomial series to show that 12123212352 224262 2242 1.3.5-....(n-1) . π when n is even Hint: You'll need to use the fact that for/2sin"(x)dx = Note that this...
The period T of a simple pendulum is given by T=2πLg−−√T=2πLg where L is the length of the...
The period T of a simple pendulum is given by T=2πLg−−√T=2πLg where L is the length of the pendulum and g is the acceleration due to gravity. Assume that g = 9.80 m/s2 exactly, and that L, in meters, is lognormal with parameters μL = 0.8 and σ2L=0.05.σL2=0.05. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Find P(T > 3).
(1 point) Suppose a pendulum with length L (meters) has angle 0 (radians) from the vertical. It can be shown that 0 as...
(1 point) Suppose a pendulum with length L (meters) has angle 0 (radians) from the vertical. It can be shown that 0 as a function of time satisfies the differential equation: d20 + -sin 0 = 0 dt2 L where g = 9.8 m/sec/sec is the acceleration due to gravity. For small values of 0 we can use the approximation sin(0) ~ 0, and with that substitution, the differential equation becomes linear A. Determine the equation of motion of a...
The period T of a pendulum with length L meters that makes a maximum angle of...
The period T of a pendulum with length L meters that makes a maximum angle of θ0 with the vertical is The vertical is: T= 4\sqrt{\frac{L}{9}}\int _0^{\frac{\pi }{2}}\frac{dx}{\sqrt{1-k^2sin^2x}} where k=sin((1/2)θ0) and g=9.8 m/sec2 in the acceleration due to gravity. (a) Find the first four terms of a series expansion for T by expanding the integrand using the binomial series and integrating term by term (your answer will include L, g, k). You may use the following integration fact: The integration...
show all steps please (1 point) Suppose a pendulum with length L (meters) has angle 0...
show all steps please
(1 point) Suppose a pendulum with length L (meters) has angle 0 (radians) from the vertical. It can be shown that 0 as a function of time satisfies the differential equation: d20 +sin0 0 dt2 where g 9.8 m/sec/sec is the acceleration due to gravity. For small values of 0 we can use the approximation sin(0)~0, and with that substitution, the differential equation becomes linear. A. Determine the equation of motion of a pendulum with length...
(1 point) Suppose a pendulum of length L meters makes an angle of θ radians with the vertical, as n the figure t can be...
(1 point) Suppose a pendulum of length L meters makes an angle of θ radians with the vertical, as n the figure t can be shown that as a function of time, θ satisfies the differential equation d20 + sin θ-0, 9.8 m/s2 is the acceleration due to gravity For θ near zero we can use the linear approximation sine where g to get a linear di erential equa on d20 9 0 dt2 L Use the linear differential equation...
(10 points) Suppose a pendulum with length L (meters) has angle (radians) from the vertical. It...
(10 points) Suppose a pendulum with length L (meters) has angle (radians) from the vertical. It can be shown that e as a function of time satisfies the differential equation: de 8 + -sin 0 = 0 dt2 L where g = 9.8 m/sec/sec is the acceleration due to gravity. For small values of we can use the approximation sin(0) - 0, and with that substitution, the differential equation becomes linear. A. Determine the equation of motion of a pendulum...
T = 4V The figure shows a pendulum with length L that makes a maximum angle...
T = 4V The figure shows a pendulum with length L that makes a maximum angle @o with the vertical. Using Newton's Second Law, it can be shown that the period T (the time for one complete swing) is given by -TT/2 dx L go 1 - k2 sin2(x) where k = sin(100) and g is the acceleration due to gravity. If L = 2 m and 60 = 46°, use Simpson's Rule with n = 10 to find the...
This is beyond me right now...
4. Extra Creait: 10 pts The period of a pendulum with length L that makes a maximum angle of 690 with the vertical is dx T/2 1-k2 sin (x) where k =sin (160) and g is the acceleration due to gravity. Expand the integrand as a binomial series to show that 12123212352 224262 2242 1.3.5-....(n-1) . π when n is even Hint: You'll need to use the fact that for/2sin"(x)dx = Note that this...
(1 point) Suppose a pendulum with length L (meters) has angle 0 (radians) from the vertical. It can be shown that 0 as a function of time satisfies the differential equation: d20 + -sin 0 = 0 dt2 L where g = 9.8 m/sec/sec is the acceleration due to gravity. For small values of 0 we can use the approximation sin(0) ~ 0, and with that substitution, the differential equation becomes linear A. Determine the equation of motion of a...
show all steps please
(1 point) Suppose a pendulum with length L (meters) has angle 0 (radians) from the vertical. It can be shown that 0 as a function of time satisfies the differential equation: d20 +sin0 0 dt2 where g 9.8 m/sec/sec is the acceleration due to gravity. For small values of 0 we can use the approximation sin(0)~0, and with that substitution, the differential equation becomes linear. A. Determine the equation of motion of a pendulum with length...
(1 point) Suppose a pendulum of length L meters makes an angle of θ radians with the vertical, as n the figure t can be shown that as a function of time, θ satisfies the differential equation d20 + sin θ-0, 9.8 m/s2 is the acceleration due to gravity For θ near zero we can use the linear approximation sine where g to get a linear di erential equa on d20 9 0 dt2 L Use the linear differential equation...
(10 points) Suppose a pendulum with length L (meters) has angle (radians) from the vertical. It can be shown that e as a function of time satisfies the differential equation: de 8 + -sin 0 = 0 dt2 L where g = 9.8 m/sec/sec is the acceleration due to gravity. For small values of we can use the approximation sin(0) - 0, and with that substitution, the differential equation becomes linear. A. Determine the equation of motion of a pendulum...
T = 4V The figure shows a pendulum with length L that makes a maximum angle @o with the vertical. Using Newton's Second Law, it can be shown that the period T (the time for one complete swing) is given by -TT/2 dx L go 1 - k2 sin2(x) where k = sin(100) and g is the acceleration due to gravity. If L = 2 m and 60 = 46°, use Simpson's Rule with n = 10 to find the...
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