Question

I need help on the last problem! I provided all the information though, in case it was needed.

For all of the graphs below use a vector x ranging from 0 to 10 in steps of 0.1. Create two additional vectors using the following formulas: yp=x.^2.5 and ym=x.^(-2.5);

[7;5] Plot yp and ym on a single plot controlling the line color and style (your choice). Put a symbol and text string at the point where the two lines cross (Create a variable holding the x and y values where the lines cross. Explain how you found this answer). Add appropriate labels and a title.

[2;3] Create a new plot of yp and ym using a log scale on the y axis. Put a symbol and text string at the location where the two lines cross. Add appropriate labels and a title.

[1;2] Create the formula for the derivative of yp (apply the rules of calculus to the formula for yp). Plot yp versus x. Add a straight line at 3 points (at x = 3, 5, 8) with the slope of the line (determined from the derivative) showing that the derivative is the slope of a tangent line at the indicated points.

Answer 1

`Hey,

Note: Brother if you have any queries related the answer please do comment. I would be very happy to resolve all your queries.

1)

clc%clears screen
clear all%clears history
close all%closes all files
x=0:0.1:10;
yp=x.^2.5;
ym=x.^(-2.5);
f=@(x) x^2.5-x^(-2.5);
disp('Point of intersection is');
xx=fzero(f,5)
yy=xx^(-2.5)
plot(x,yp,x,ym);
legend('x^{2.5}','x^{-2.5}');
text(xx,yy,['(' num2str(xx) ', ' num2str(yy) ')']);
title('Plot 1');

Note: Brother According to Chegg's policy we are only allowed to answer first part if there are many. So, I request you to post other part as separate posts.

Kindly revert for any queries

Thanks.