JAVA 3.Consider the following sequence of steps to add a node to the front of a...
JAVA
3.Consider the following sequence of steps to add a node to the front of a linked list: - Set the reference field to refer to the first node in the current list. - Set the reference to the front of the list to refer to the new node. Is the order of these steps important? Explain your answer.
Homework Answers
The steps to add a node to the front of a linked list:
-> Create the Node to be added.
-> Set the reference field of above Node to refer the front Node
-> Set the above Node as the new front Node
The order of these statements is very important, because if we set the reference to the front of the list to refer to the new node before we position the new node before current front node, the previous contents of the linked list will be lost.
For example, consider a linked list below.
Front: 3 -> 5 -> 7
Suppose we want to add the node with value 1 to the front. So as per the correct order of steps to add, we initially set the next/reference field of new node (1) to the current front node. So Node with value 1 will point to the Node with value 3, which is current front node, and then we set node with value 1 as the new front node.
Resultant list will be
Front: 1 -> 3 -> 5 -> 7
But if we set Node 1 as the new front node before setting current front as next of Node with value 1, then the resultant list will be
Front: 1
And after we assign reference to the first node in the current list as the next of this new node, then front will be pointing to itself. That is, next of Node with value 1 will be the same Node with value 1.
I hope you are clear now. Let me know if you have any doubts or if you need anything to change. If you are satisfied with the solution, please rate the answer. Thanks
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