Ammonia reacts with oxygen to form nitrogen dioxide and steam, as follows: 4 NH3(g) + 7...

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Ammonia reacts with oxygen to form nitrogen dioxide and steam, as follows:

4 NH₃(g) + 7 O₂(g) ---> 4 NO₂(g) + 6 H₂O(g)

Use the following data for bond energies to determine the determine the enthalpy of the reaction.

O−H : 459 kJ/mol
N−H : 386 kJ/mol
N−O : 201 kJ/mol
N=O : 607 kJ/mol
O=O : 494 kJ/mol

The answer my professor gives is -4163 kJ/mol but I don't know how to get that answer especially with the bonds on NO₂

Answer 1

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