Ammonia reacts with oxygen to form nitrogen dioxide and steam, as follows: 4NH3(g) + 7O2(g) --->...

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Question

Ammonia reacts with oxygen to form nitrogen dioxide and steam, as follows:

4NH3(g) + 7O2(g) ---> 4NO2(g) + 6H2O(g)

Using the following bond energies, estimate the enthalpy change for the reaction.

BE(O–H) = 464 kJ/mol

BE(N–H) = 389 kJ/mol

BE(O=O) = 498 kJ/mol

BE(N–O) = 222 kJ/mol

BE(N=O) = 590 kJ/mol

Answer 1

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