Homework Answers
Answer
24.0L
Explanation
4NH3 + 5O2 -----> 4NO + 6H2O
Stoichiometrically, 5 moles of O2 gives 4moles of NO
Ideal gas equation is
PV = nRT
P = Pressure , 0.987atm
V = Volume , 30L
n = number of moles, ?
R = gas constant, 0.082057(L atm/mol K)
T = Temperature , 850℃= 1123.15K
n = PV/RT
= 0.987atm × 30L /(0.082057(L atm/mol K) × 1123.15K)
= 0.3213mol
0.3213 moles of O2 should give (4/5)×0.3213mol = 0.2570moles of NO
V = nRT/P
= 0.2570mol × 0.082057(L atm/mol K) × 1123.15K/0.987atm
= 24.0L
Therefore
Volume of NO produced = 24.0L
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