If A and B are events with P(A)=0.4, P(A OR B)=0.52, and P(A AND B)=0.08, find P(B). Provide your answer below:
If A and B are events with P(A)=0.4, P(A OR B)=0.52, and P(A AND B)=0.08, find...
Events A and B are independent with p(A) - 0.2 and p(B) - 0.4. Find p(A union B). O 0.52 0.08 O 0.6
(1) Suppose that A and B are events with P[A] = 0.4 and P[B] = 0.7. Show that 0.1 < PAB < 0.4. Justify your answer clearly. P(ANB) - PCA) PCB) = 0.4.0.7 = 0.28 with 0.15 0.28 <0.4 PLA) occuring 04 P(B) occuring 0.7 P of both events occuring at the same time should be = 0.28 which is in Ran 0,4 1028 0.7 2/10
Two events A and B are such that P(A) = 0.4, P(B) = 0.5, and P(AUB) = 0.7. (a) Find P(A n B). 0.2 (b) Find P(AUB). 0.8 (c) Find P(An B). 0.3 (d) Find P(AB). (Enter your probability as a fraction.) 1/2
For two events, A and B, P(A) = 0.4 and P(B) = 0.3 (a) If A and B are independent, find ?(? ∩ ?), ?(?|?), ?(? ∪ ?). (b) If A and B are dependent with ?(?|?) = 0.6, find ?(? ∪ ?),?(?|?).
For two events, A and B, P(A) = 0.4 and P(B) = 0.3 (a) If A and B are independent, find ?(? ∩ ?), ?(?|?), ?(? ∪ ?). (b) If A and B are dependent with ?(?|?) = 0.6, find ?(? ∪ ?),?(?|?).
Tesponse. Question 6 Let A and B be two events, such that P(A)=0.6, P(B)=0.4 and P((not A) and (not B))=0.2. (6 Please give your answer as simplified fraction or decimal number (e.g. 3/4 or 0.75) a) Find P(A or B)= 0.76 b) Find P((not A) and (B))= || I c) Find P( AB)=
1. The events A and B are such that P(A) = 0.4, P(B) = 0.6 and P(A U B) = 0.7. Find P(A' U B'). Show diagrams.
If A and B are independent events with P(A)=0.3 and P(B)=0.9, find P(A AND B). Provide your answer below:
A and B are two events such that P(A) = 0.4, P(B) = 0.5, and P(A|B) = 0.3. Find P(A and B). Select one: a. 0.6 b. 0.15 c. 0.12 d. 0.2
For two events, A and B, P(A) = 0.4 and P(B) = 0.35 a. If A and B are independent, find P(A B), P(A l B), P(A B). b. If A and B are dependent with P(A l B) = 0.6, find P(A B), P(B l A). We were unable to transcribe this imageWe were unable to transcribe this imageWe were unable to transcribe this image