Solution :
(a)
P(A B) = P(A ) + P(B) - P(A B)
= 0.4 + 0.5 - 0.7
= 0.2
(b)
P(Ac B c) = P(A B)c = 1 - P(A B) = 1 - 0.2 = 0.8
(c)
P(Ac B c) = P(A B)c = 1 - P(A B) = 1 - 0.7 = 0.3
(d)
P(Ac | B ) = = P(Ac B) / P(B) = [P(B) - P(A B)] / P(B)
= [0.5 - 0.2] / 0.5
= 0.3 / 0.5
= 0.6
Two events A and B are such that P(A) = 0.4, P(B) = 0.5, and P(AUB)...
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