A proton is launched with initial velocity 1.05x106 m/s in the -x direction into a region...
A proton is launched with initial velocity 1.05x106 m/s in the -x direction into a region of magnetic field B = 0.140 T in the +y direction. Find the force acting on and the acceleration of the proton.
Answer: 2.35x10E-14 N in -z direction 1.41x10E+13 m/s^2 in the -z direction.
Redo problem if the velocity were instead directed at an angle of 37 degrees from the -x direction towards the +y direction.
Answer: 1.88x10-14 N in the -z direction 1.12x10+13 m/s^2 in the -z direction
Show all formulas used
Homework Answers
Add Answer to:
A proton is launched with initial velocity 1.05x106 m/s in the
-x direction into a region...
A proton is traveling with an initial velocity of (7 x 10^4) m/s in the "i...
A proton is traveling with an initial velocity of (7 x 10^4) m/s in the "i hat" direction and is subject to the gravitational force of the earth. What is the magnitude and direction of the magnetic field needed to keep the proton moving in the x direction if it enters a region of uniform magnetic field.
A proton is launched with a speed of 4.50 x 106 m/s perpendicular to a uniform...
A proton is launched with a speed of 4.50 x 106 m/s perpendicular to a uniform magnetic field of 0.360 T in the positive z direction. (a) What is the radius of the circular orbit of the proton? cm (b) What is the frequency of the circular movement of the proton in this field? Hz
A proton moving in the positive x direction with a speed of 9.1 105 m/s experiences...
A proton moving in the positive x direction with a speed of 9.1 105 m/s experiences zero magnetic force. When it moves in the positive y direction it experiences a force of 1.8 10-13 N that points in the positive z direction. Determine the magnitude and direction of the magnetic field. magnitude T
A proton, moving at a velocity of 681 m/s experiences an acceleration of 2.0 x 1014...
A proton, moving at a velocity of 681 m/s experiences an acceleration of 2.0 x 1014 m/s2 when it enters a magnetic field at an angle of 55 degrees to the field. Calculate the strength of the magnetic field. Assume that the force from the magnetic field is the only force acting on the proton. (Hint: You will need to solve for this force first!)
A proton is projected in the positive x direction into a region of uniform electric field = (-5.60 105) N/C at t = 0...
A proton is projected in the positive x direction into
a region of uniform electric field = (-5.60 105)
N/C at t = 0. The proton travels 6.30 cm as it comes to rest.
(a) Determine the acceleration of the
proton.
(b) Determine the initial speed of the proton.
(c) Determine the time interval over which the proton comes to
rest.
s
magnitude
m/s2
direction
---Select--- +x −x +y −y +z −z
magnitude
m/s
direction
---Select--- +x −x +y −y...
8. An electron is launched along the x-direction into a region where both a uniform electric...
8. An electron is launched along the x-direction into a region where both a uniform electric and magnetic field are present. The electric field is known to point along the y- direction and the magnetic field's x-component is known to be zero. Furthermore, the figure below shows the y-component of the net force on the particle as a function of the speed with which it is launched into the field region. This means that different launch speeds amount to different...
A proton with an initial speed of 1.80 ✕ 108 m/s in the +x direction collides...
A proton with an initial speed of 1.80 ✕ 108 m/s in the +x direction collides elastically with another proton initially at rest. The first proton's velocity after the collision is 1.492 ✕ 108 m/s at an angle of 34.0° with the +x-axis. What is the velocity (magnitude and direction) of the second proton after the collision? magnitude m/s direction ° counterclockwise from the +x-axis
A proton with a speed of 2.20×106 m/s is shot into a region between two plates...
A proton with a speed of 2.20×106
m/s is shot into a region between two plates that are separated by
a distance of 0.185 m. As the drawing shows, a magnetic field
exists between the plates, and it is perpendicular to the velocity
of the proton. What must be the magnitude of the magnetic field (in
T), so the proton just misses colliding with the opposite
plate?
what are the steps and formulas to acquire this answer?
An object is launched at a velocity of 33 m/s in a direction making an angle...
An object is launched at a velocity of 33 m/s in a direction making an angle 34 degrees upward with the horizontal. What is the total flight time of the object ? (assume g = 9.81 m/s2)
A proton in a particle accelerator has a speed of 5.0 x 10^6 m / s....
A proton in a particle accelerator has a speed of 5.0 x 10^6 m / s. The proton is found with a magnetic field whose magnitude is 0.40 T and its direction is 30 degrees with respect to the speed of the proton. Find the magnitude of the magnetic force acting on the proton and find its acceleration.
A proton is launched with a speed of 4.50 x 106 m/s perpendicular to a uniform magnetic field of 0.360 T in the positive z direction. (a) What is the radius of the circular orbit of the proton? cm (b) What is the frequency of the circular movement of the proton in this field? Hz
A proton is projected in the positive x direction into
a region of uniform electric field = (-5.60 105)
N/C at t = 0. The proton travels 6.30 cm as it comes to rest.
(a) Determine the acceleration of the
proton.
(b) Determine the initial speed of the proton.
(c) Determine the time interval over which the proton comes to
rest.
s
magnitude
m/s2
direction
---Select--- +x −x +y −y +z −z
magnitude
m/s
direction
---Select--- +x −x +y −y...
8. An electron is launched along the x-direction into a region where both a uniform electric and magnetic field are present. The electric field is known to point along the y- direction and the magnetic field's x-component is known to be zero. Furthermore, the figure below shows the y-component of the net force on the particle as a function of the speed with which it is launched into the field region. This means that different launch speeds amount to different...
A proton with a speed of 2.20×106
m/s is shot into a region between two plates that are separated by
a distance of 0.185 m. As the drawing shows, a magnetic field
exists between the plates, and it is perpendicular to the velocity
of the proton. What must be the magnitude of the magnetic field (in
T), so the proton just misses colliding with the opposite
plate?
what are the steps and formulas to acquire this answer?
Most questions answered within 3 hours.
-
Which of the following ratios would be considered a measurement
of short-term liquidity?
Select one:
a....
asked 3 seconds ago -
Nitrogen dioxide is one of the many oxides of nitrogen (often
collectively called "NOx") that are...
asked 9 minutes ago -
1/ Using ________________ as they are intended is the best
guarantee for consistency and forward compatibility....
asked 19 minutes ago -
Portfolio theory
Given the following information about firm A and the
market:δ
E (Rm)= 12 per...
asked 16 minutes ago -
Albert files his income tax return (showing a total tax of
$23,000) 5½ months after the...
asked 20 minutes ago -
This exercise involves you using imagination and logical
reasoning to occupy the mindset of a visualiser...
asked 30 minutes ago -
What kinds of storage have you seen in use during your own
lifetime?
asked 31 minutes ago -
Practicing Acid Base Calculations
Cameco in Port Hope, Ontario uses hydrofluoric acid to make a
uranium...
asked 38 minutes ago -
The gross payoffs (X) from the investment have the following
probability mass function.
x
p(x)
0...
asked 45 minutes ago -
In an aqueous mixture of aluminum, lead, and iron salts, which
of these will be reduced...
asked 1 hour ago -
The probability of college students in the US is given by P(A)=
0.06. The probability of...
asked 44 minutes ago -
Water is needed to supply a canal system, which may require up
to 30m3 s -1...
asked 49 minutes ago