Question

C++ question

#include <iostream>

using namespace std;

void printReverse(int);

int main() {

    int number = 12345;

    cout << "Original : " << number << endl;

    cout << "Reversed : ";

    printReverse(number);

}

void printReverse(int x) {

    if (x == 0)

       return;

    cout << x % 10;

    printReverse(x /= 10);    

}

Modify the above recursive program to output the number in the same order. Note that the program still should break up the number and then output it in the same order

12345 ? 12345

Answer 1

Program:

#include <iostream>

using namespace std;

void printReverse(int);

int main() {

int number = 12345;

cout << "Original : " << number << endl;

cout << "Reversed : ";

printReverse(number);

}

void printReverse(int x) {

int flag = 0,n,i;

if(x != 0){

printReverse(x/10);

cout<<x%10; // write the statement after the recursive call

}

return;

}

Output: