Ans :
The balanced equation is given as :
Mg(HCO3)2 + 2HIO4 = Mg(IO4)2 + 2H2O + 2CO2
Number of mol of magnesium bicarbonate = molarity x volume (L)
= 1.5 M x 0.065 (L)
= 0.0975 mol
number of mol of acid required = 2 x 0.0975 mol = 0.195 mol
mol of acid available = mass / molar mass
= 35.5 g / 191.91 g/mol = 0.185 mol
So HIO4 is limiting reagent
Then the number of moles of CO2 gas formed will be 0.185 mol
Mass of gas = mol x molar mass
= 0.185 mol x 44.01 g/mol
= 8.14 grams
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