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How many grams of iodine (I2) are produced when 32.00 ml of 0.115 M NaOCl reacts...

How many grams of iodine (I2) are produced when 32.00 ml of 0.115 M NaOCl reacts with 25.0 ml of 0.175 M KI (and excess H+ )?

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→ The objective is to how many gram, determine produced. of lodine (92) are No.of moles of Naoc 0 .115m 32.00 ML Naocel - volof I, millimolee 2.1875 mdar mass of I, = 253.8 So, mass of I, - (millimales of 12 ) ( moler mass $1.) = 62.18454103) ( 253.8

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