Suppose a random sample of size 64 is selected from a population. The sample yields a mean of 26 and a standard deviation of 4. From this information, the 90% confidence interval to estimate the population mean can be computed to be _______.
Solution :
Given that,
Point estimate = sample mean = = 26
Population standard deviation =
= 4
Sample size = n =64
At 90% confidence level the z is ,
= 1 - 90% = 1 - 0.90 = 0.1
/ 2 = 0.1 / 2 = 0.05
Z/2 = Z0.05 = 1.645 ( Using z table )
Margin of error = E = Z/2 * (
/n)
= 1.645 * ( 4 / 64
)
= 0.8225
At 90% confidence interval estimate of the population mean
is,
- E <
<
+ E
26 - 0.8225 <
< 26 + 0.8225
25.1775 <
< 26.8225
Suppose a random sample of size 64 is selected from a population. The sample yields a...
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