You are planning to make monthly deposits of $90 into a retirement account that pays 9 percent annual interest (APR), compounded monthly. If your first deposit will be made one month from now, how large will your retirement account be in 27 years?
Solution: | ||
Value of retirement account be in 27 years is $123,076.25 | ||
Working Notes: | ||
Value of retirement account be in 27 years is the future value of annuity of monthly deposit. | ||
Future value of annuity = P x ((1+i)^n - 1)/i | ||
P= Monthly deposits= $90 | ||
i= monthly rate =APR/12 = 9%/12 = 0.75% | ||
n= no. Of payments x no. Of years | ||
= 12 x 27 =324 | ||
Future value of annuity = Value of retirement account be in 27 years | ||
Future value of annuity | ||
= P x ((1+i)^n - 1)/i | ||
= 90 x ((1+0.75%)^324 - 1)/0.75% | ||
=$123,076.2532 | ||
=$123,076.25 | ||
Value of retirement account be in 27 years is $ | 123,076.25 | |
Please feel free to ask if anything about above solution in comment section of the question. |
SOLUTION ;
Monthly compounding.
First deposit will be made one month from now.So, it is ordinary annuiy case.
Monthly deposit, A = 90 ($)
Monthly interest rate , r = 9/12 % = 3/4% = 3/400 in fractions.
=> 1 + r = 1 + 3/400 = 403/400
Monthly periods, n = 27 * 12 = 324 months.
So,
Amount in the account after 27 years (324 months) as per ordinary annuity :
= A * ((1 + r)^n - 1) / r
= 90((403/400)^324 - 1) / (3/400)
= 123076.25 ($) (ANSWER).
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