A uniform bar of mass m = 0.4 kg and length L = 0.8m is articulated...
A uniform bar of mass m = 0.4 kg and length L = 0.8m is articulated around one end and oscillates in a vertical plane. Find the period of oscillation if the range of motion is small. Icm = (1/12) mL ^ 3
Homework Answers
We need to find moment of inertia about the pivot.
Therefore, we will use parallel axis theorem
Ipivot = Icm + md2
Ipivot = mL2 / 12 + m (L/2)2
Ipivot = mL2 / 3
for small angle ( small range of motion)
T = 2
sqrt ( I / mgh)
where h = L/2
so,
T = 2 sqrt (
2mL2 / 3mgL)
T = 2 sqrt (2L / 3g)
T = 2 sqrt (2 * 0.8 / 3 *
9.8)
T = 1.465 sec
Add Answer to:
A uniform bar of mass m = 0.4 kg and length L = 0.8m is articulated...
A uniform rod of mass M and length L=1.6 m is pivoted about one end and...
A uniform rod of mass M and length L=1.6 m is pivoted about one end and oscillates in a vertical plane. Find the period of oscillation if the amplitude of the motion is small. Pivot Mg
A uniform rod of mass M and length L=1.6 m is pivoted about one end and...
A uniform rod of mass M and length L=1.6 m is pivoted about one end and oscillates in a vertical plane. Suppose the pivot is located at a small hole drilled in the rod at a distance L/4 from the upper end. What is the period of oscillation of the rod when it is hung from this pivot point and swings through small oscillations? Pivot Mg
A uniform rod of mass 454 g and length 0.735 m is pivoted about one end...
A uniform rod of mass 454 g and length 0.735 m is pivoted about one end and oscillates in a vertical plane. Find the period of oscillations if the amplitude of the motion is small. The acceleration of gravity is 9.8 m/s^2 Answer in units of s.
3. Physical Pendulum. A uniform trapezoidal mass of 50 g, moment of inertia 0.050 kg. 0.0107...
3. Physical Pendulum. A uniform trapezoidal mass of 50 g, moment of inertia 0.050 kg. 0.0107 m2 with center of mass and dimension as shown is pivoted about one end and oscillates about a vertical plane. 70 cm Height = 60 cm Pivot CM d=55 cm 50 cm a) Find the period of oscillation if the amplitude of motion is small and with pivot to center of mass distance of 55 cm. b) Find the period of oscillation if the...
[7.] A uniform rod with mass M, length L, and moment of inertial with respect to...
[7.] A uniform rod with mass M, length L, and moment of inertial with respect to the center of mass Icm = MLis hinged at one end (point P) so that it can rotate, without friction, around a horizontal axis. The rod is initially held at rest forming an angle with the vertical (see figure) and then released. a) Find the moment of inertia Ip of the rod with respect to point P. b) Find the magnitude of the angular...
The mass of uniform bar ABC is MBAR = 30 kg and its overall length is...
The mass of uniform bar ABC is MBAR = 30 kg and its overall length is L=1.6 m. The bar rotates around point 0 and force F(t) is being to the end of the bar at C. The masses of pistons A and B are ma = 5 kg and mg = 8 kg , respectively. k= 20000 N/m for each spring and c=500 N-s/m for the damper connected to piston A. Coordinate e locates the bar, coordinate x, locates...
A uniform slender bar of mass M = 3.2 kg and length L = 1.78 m...
A uniform slender bar of mass M = 3.2 kg and length L = 1.78 m is translating on the smooth horizontal x-y plane with a velocity vm= 1.80 m/s when a particle of mass m = 0.36 kg traveling with a velocity Vm=5.52 m/s as shown strikes and becomes embedded in the bar. Determine the final linear velocity of the center of mass of the system and the angular velocity of the bar with its embedded particle. 3L 4...
L=1.50 m M= 2,33 kg 2. A bar of mass M, and of length L is...
L=1.50 m
M= 2,33 kg
2. A bar of mass M, and of length L is initially at rest in the vertical position shown. It starts to rotate about the hinged support at A from its vertical position. Determine the s the tupport reactions in normal and tangential directions at A when the bar is in horizontal position. Each student should find the corresponding numerical values of length in (m) and mass in (kg) on the next Page. (30 Points)...
A uniform rod of mass m-6 kg has length L = 60 cm . Instead of...
A uniform rod of mass m-6 kg has length L = 60 cm . Instead of pivoting it at its end, we pivoted it at L/3 from the end as shown in the figure, we now set the rod into small angle oscillations. What is the period of the oscillation given that the moment of inertia about the pivot point is ml2/9? L/3 Pivot L С.М. 2L/3
A uniform rod of mass m- 9 kg has length L-70 cm. Instead of pivoting it...
A uniform rod of mass m- 9 kg has length L-70 cm. Instead of pivoting it at its end, we pivoted it at L/3 from the end as shown in the figure. We now set the rod into small angle oscillations. What is the period of the oscillation given that the moment of inertia about the pivot point is mL2/9? L/3 Pivot L с.м. 2L/3
A uniform rod of mass M and length L=1.6 m is pivoted about one end and oscillates in a vertical plane. Find the period of oscillation if the amplitude of the motion is small. Pivot Mg
A uniform rod of mass M and length L=1.6 m is pivoted about one end and oscillates in a vertical plane. Suppose the pivot is located at a small hole drilled in the rod at a distance L/4 from the upper end. What is the period of oscillation of the rod when it is hung from this pivot point and swings through small oscillations? Pivot Mg
A uniform rod of mass 454 g and length 0.735 m is pivoted about one end and oscillates in a vertical plane. Find the period of oscillations if the amplitude of the motion is small. The acceleration of gravity is 9.8 m/s^2 Answer in units of s.
3. Physical Pendulum. A uniform trapezoidal mass of 50 g, moment of inertia 0.050 kg. 0.0107 m2 with center of mass and dimension as shown is pivoted about one end and oscillates about a vertical plane. 70 cm Height = 60 cm Pivot CM d=55 cm 50 cm a) Find the period of oscillation if the amplitude of motion is small and with pivot to center of mass distance of 55 cm. b) Find the period of oscillation if the...
[7.] A uniform rod with mass M, length L, and moment of inertial with respect to the center of mass Icm = MLis hinged at one end (point P) so that it can rotate, without friction, around a horizontal axis. The rod is initially held at rest forming an angle with the vertical (see figure) and then released. a) Find the moment of inertia Ip of the rod with respect to point P. b) Find the magnitude of the angular...
The mass of uniform bar ABC is MBAR = 30 kg and its overall length is L=1.6 m. The bar rotates around point 0 and force F(t) is being to the end of the bar at C. The masses of pistons A and B are ma = 5 kg and mg = 8 kg , respectively. k= 20000 N/m for each spring and c=500 N-s/m for the damper connected to piston A. Coordinate e locates the bar, coordinate x, locates...
A uniform slender bar of mass M = 3.2 kg and length L = 1.78 m is translating on the smooth horizontal x-y plane with a velocity vm= 1.80 m/s when a particle of mass m = 0.36 kg traveling with a velocity Vm=5.52 m/s as shown strikes and becomes embedded in the bar. Determine the final linear velocity of the center of mass of the system and the angular velocity of the bar with its embedded particle. 3L 4...
L=1.50 m
M= 2,33 kg
2. A bar of mass M, and of length L is initially at rest in the vertical position shown. It starts to rotate about the hinged support at A from its vertical position. Determine the s the tupport reactions in normal and tangential directions at A when the bar is in horizontal position. Each student should find the corresponding numerical values of length in (m) and mass in (kg) on the next Page. (30 Points)...
A uniform rod of mass m-6 kg has length L = 60 cm . Instead of pivoting it at its end, we pivoted it at L/3 from the end as shown in the figure, we now set the rod into small angle oscillations. What is the period of the oscillation given that the moment of inertia about the pivot point is ml2/9? L/3 Pivot L С.М. 2L/3
A uniform rod of mass m- 9 kg has length L-70 cm. Instead of pivoting it at its end, we pivoted it at L/3 from the end as shown in the figure. We now set the rod into small angle oscillations. What is the period of the oscillation given that the moment of inertia about the pivot point is mL2/9? L/3 Pivot L с.м. 2L/3
Most questions answered within 3 hours.
-
Preparation of Benzoic Acid using a Grignard Reagent URGENT
1. During your Grignard formation, a small...
asked 13 minutes ago -
A uniform magnetic field is perpendicular to the plane of a wire
loop. If the loop...
asked 11 minutes ago -
At the peak of your career, your were earning $120,000 and
holding a top level position....
asked 15 minutes ago -
. A permanent magnet is dropped south-end-down through a horizontal
circular coil with a radius of...
asked 17 minutes ago -
Bernie's Beverages purchased some fixed assets classified as
5-year property for MACRS. The assets cost $28,000....
asked 31 minutes ago -
How many ATPs are produced from the catabolism of a 10-C
molecule of fatty acid under...
asked 35 minutes ago -
Before practicing a routine on the rings, a 64.8 kg gymnast
hangs motionless, with one hand...
asked 37 minutes ago -
If the K b of a weak base is 6.3 × 10 − 6 , what...
asked 43 minutes ago -
Which of the following is the minimum amount of moles of NaOH
that must be added...
asked 47 minutes ago -
Stories about organizational ________ provide important clues
about cultural values and norms.
a. myths
b. heroes...
asked 49 minutes ago -
Explain the criteria used in selecting a target market
BUS220 Retail Management, thank you!
asked 51 minutes ago -
Convert/Calculate the following:
Determine the identity of an elemental gas if 4.55 L weighing
35.4g, under...
asked 54 minutes ago