Why a Substance Can Be a Liquid at Room Temperature? Calculate ΔS∘total for the evaporation of...
Why a Substance Can Be a Liquid at Room Temperature?
Calculate ΔS∘total for the evaporation of water at 25∘C.
H2O (l) ⇄ H2O (g)
ΔH∘f (kJ/mol) Sm∘ (J/mol*K)
H2O (l) - 285.830 69.91
H2O (g) - 241.818 188.83
ΔS∘ system?
ΔS∘surroundings?
ΔS∘total?
Homework Answers
ΔS∘ = ΔS∘ products - ΔS∘ reactants
= 188.83 - 69.91
= 118.92 J / mol K
ΔS∘ system = 118.92 J / mol K
ΔH∘ = -241.818 - (-285.830)
= 44.012 kJ / mol
ΔS∘surroundings = - ΔH∘ / T
= -44012 / 298.15
= -147.62 J / mol . K
ΔS∘surroundings = -147.62 J / mol . K
ΔS∘total = ΔS∘ system + ΔS∘ surrounds
= 118.92 - 147.62
= -28.70 J / mol.K
ΔS∘total = - 28.70 J / mol.K
ΔS∘total will be negative here . so that H2O will be existed as liquid at room temperature . it not is spontaneous to convert to gas at room temperature
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