You dump 255 g of unknown metal (at 125 C) into a 955 g vat of...
You dump 255 g of unknown metal (at 125 C) into a 955 g vat of water at 20.0 C, and the
final temperature of both is 35.7 C. What is the specific heat of the unknown? Assume NO water I lost...
Homework Answers
Here ,
let the specific heat of unknown is S
for the heat
heat lost by metal = heat lost by water
955 * 4.186 * (35.7 - 20) = 255 * S * (125 - 35.7)
solving for S
S = 2.76 J/(gm. degree C) = 2760 J/(kg.degree C)
the specific heat of unknown is 2760 J/(kg.degree C)
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