4. You placed 43.1 g of an unknown metal at 100 °C into a coffee cup...
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4. You placed 43.1 g of an unknown metal at 100 °C into a coffee cup calorimeter that contained 50.0 g of water that was initially at 22.0 °C. The equilibrium temperature of mixing (T0) was determined to be 23.7 °C. The calorimeter constant was known to be 51.5 J/°C. Specific HeatH2O = 4.184 J/g·°C |
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a. What is the total amount of heat (J) lost by the metal? |
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b. What was the specific heat (J/g·°C) of the metal? |
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Homework Answers
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4. You placed 43.1 g of an unknown metal at 100 °C into a coffee
cup...
PART A: A student constructs a coffee cup calorimeter and places 50.0 mL of water into...
PART A: A student constructs a coffee cup calorimeter and places 50.0 mL of water into it. After a brief period of stabilization, the temperature of the water in calorimeter is determined to be 19.6 °C. To this is added 50.0 mL of water that was originally a temperature of 54.5 °C. A careful plot of the recorded temperature established T0 as 31.1 °C. What is the calorimeter constant (J/°C)? DensityH2O = 1.00 g/mL Specific HeatH2O = 4.184 J/g·°C PART...
5. (2) The coffee cup calorimeter, although a good insulator, does absorb some heat during each...
5. (2) The coffee cup calorimeter, although a good insulator, does absorb some heat during each experiment. If a calorimeter constant is not determined, how would this affect the specific heat of the metal? Be specific. 6. (3) An unknown metal weighing 13.11 g at a temperature of 81.0 °C is place in a calorimeter containing 25.0 mL of water at a temperature of 25.0 °C. The final equilibrium temperature is 30.0 °C. What is the specific heat of the...
A piece of metal with specific heat 0.1300 J/g oC is placed in a coffee cup...
A piece of metal with specific heat 0.1300 J/g oC is placed in a coffee cup calorimeter containing 432 g water at 18.00 oC. The temperature of the water rose to 25.70 oC. How much heat in kJ was lost by the metal?
4. You mix 50.0 ml. of a weak monoprotic acid with 50.0 mL of NaOH solution...
4. You mix 50.0 ml. of a weak monoprotic acid with 50.0 mL of NaOH solution in a coffee cup calorimeter. Both solutions and the calorimeter were initially at 23.9°C. The final temperature of the neutralization reaction was determined to be 41.2°C. The calorimeter constant was known to be 110.6J/°C. Density Aqueous Solution = 1.00 g/ml Specific Heat of water = 4.184 J/g °C Hide a. What is the total amount of heat evolved in this reaction? NG 3 b....
3. A student constructs a coffee cup calorimeter and places 50.0 mL of water into it....
3. A student constructs a coffee cup calorimeter and places 50.0 mL of water into it. After a brief period of stabilization, the temperature of the water in the calorimeter is determined to be 22.7 °C. To this is added 50.0 mL of water that was originally at a temperature of 54.5 C. A careful plot of the temperatures recorded after this established the temperature at To was 30.24 C. What is the calorimeter constant in J/C for this calorimeter?...
A 10.95 g sample of lead at 88.0°C was placed into a styrofoam cup calorimeter which...
A 10.95 g sample of lead at 88.0°C was placed into a styrofoam cup calorimeter which contained 15 mL of water at 22.0°C. The final temperature in the calorimeter reached 23.5°C. Calculate the specific heat of lead. The specific heat of water is 4.184 J/g°C.
A student constructs a coffee cup calorimeter and places 50.0 mL of water into it. After...
A student constructs a coffee cup calorimeter and places 50.0 mL of water into it. After a brief period of stabilization, the temperature of the water in calorimeter is determined to be 19.9 °C. To this is added 50.0 mL of water that was originally a temperature of 54.2 °C. A careful plot of the recorded temperature established T0 as 31.9 °C. What is the calorimeter constant (J/°C)? DensityH2O = 1.00 g/mL Specific HeatH2O = 4.184 J/g·°C
A 69.62 g block of lead is heated to 99.48ºC and is placed into a coffee-cup...
A 69.62 g block of lead is heated to 99.48ºC and is placed into a coffee-cup calorimeter filled with 75.67 g of water initially at 22.07ºC. The final temperature was measured as 24.58ºC. The calorimeter heat capacity is 1.860 J/ºC and the specific heat of water is 4.184 J/ g ºC. Based on this information, what is the specific heat of lead? a.0.1473 J/ g ºC b.0.1481 J/ g ºC c.0.1523 J/ g ºC d.0.1533 J/ g ºC e.0.2109 J/...
E AFTER COMPLETING LAB. ANSWER IN SPACE PROVIDED. Suppose the heat of neutralization had been determined using a glass beaker instead of a polystyrene coffee cup How would the measured value have...
E AFTER COMPLETING LAB. ANSWER IN SPACE PROVIDED. Suppose the heat of neutralization had been determined using a glass beaker instead of a polystyrene coffee cup How would the measured value have been affected? The heat of combustion of octane, C,H,. can be measured in a way similar to the method youC used to measure the heat of neutralization. The bomb calorimeter is used instead of a coffee cup. The reaction is 2C,H,1)+ 25 O, (g) 16 CO, (g) +...
7. A coffee cup calorimeter contains 150 g of water at 25.1 °C. A 121 g...
7. A coffee cup calorimeter contains 150 g of water at 25.1 °C. A 121 g block of solid copper is placed into the water and the temperature of the water and block goes to 30.1 °C. What was the perature of the copper block? The specific heat of solid copper metal is 0.385 J/g-°C and the specific heat of water is 4.184 J/g-°C. Assume that the calorimeter doesn't absorb any heat.
5. (2) The coffee cup calorimeter, although a good insulator, does absorb some heat during each experiment. If a calorimeter constant is not determined, how would this affect the specific heat of the metal? Be specific. 6. (3) An unknown metal weighing 13.11 g at a temperature of 81.0 °C is place in a calorimeter containing 25.0 mL of water at a temperature of 25.0 °C. The final equilibrium temperature is 30.0 °C. What is the specific heat of the...
4. You mix 50.0 ml. of a weak monoprotic acid with 50.0 mL of NaOH solution in a coffee cup calorimeter. Both solutions and the calorimeter were initially at 23.9°C. The final temperature of the neutralization reaction was determined to be 41.2°C. The calorimeter constant was known to be 110.6J/°C. Density Aqueous Solution = 1.00 g/ml Specific Heat of water = 4.184 J/g °C Hide a. What is the total amount of heat evolved in this reaction? NG 3 b....
3. A student constructs a coffee cup calorimeter and places 50.0 mL of water into it. After a brief period of stabilization, the temperature of the water in the calorimeter is determined to be 22.7 °C. To this is added 50.0 mL of water that was originally at a temperature of 54.5 C. A careful plot of the temperatures recorded after this established the temperature at To was 30.24 C. What is the calorimeter constant in J/C for this calorimeter?...
E AFTER COMPLETING LAB. ANSWER IN SPACE PROVIDED. Suppose the heat of neutralization had been determined using a glass beaker instead of a polystyrene coffee cup How would the measured value have been affected? The heat of combustion of octane, C,H,. can be measured in a way similar to the method youC used to measure the heat of neutralization. The bomb calorimeter is used instead of a coffee cup. The reaction is 2C,H,1)+ 25 O, (g) 16 CO, (g) +...
7. A coffee cup calorimeter contains 150 g of water at 25.1 °C. A 121 g block of solid copper is placed into the water and the temperature of the water and block goes to 30.1 °C. What was the perature of the copper block? The specific heat of solid copper metal is 0.385 J/g-°C and the specific heat of water is 4.184 J/g-°C. Assume that the calorimeter doesn't absorb any heat.
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