Question

The combined SAT scores for the students at a local high school are normally distributed with a mean of 1453 and a standard deviation of 297. The local college includes a minimum score of 651 in its admission requirements.

What percentage of students from this school earn scores that fail to satisfy the admission requirement?
P(X < 651) = %

Enter your answer as a percent accurate to 1 decimal place (do not enter the "%" sign). Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.

Answer 1

Solution :

Given that ,

mean = = 1453

standard deviation = = 297

P(x < 651)

= P[(x - ) / < (651 - 1453) / 297]

= P(z < -2.700)

Using z table,

= 0.004

The percent = 0.4