Suppose a random variable X has support {1,2,3,4,5} and that P(X
= 1) = P(X = 2) =
2P(X = 3) = 2P(X = 4) = 3P(x = 5). Find the distribution of X and
E[X]. .
P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)=1
P(X=1)+P(X=1)+P(X=1)/2+P(X=1)/2+P(X=1)/3=1
(6P(X=1)+6P(X=1)+3P(X=1)+3P(X=1)+2P(X=1))/6=1
20P(X=1)/6=1
P(X=1)=6/20=0.3
Distribution of X is
X. P
1. 0.3
2. 0.3
3. 0.15
4. 0.15
5. 0.1
E(X)
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