Question

What does this print to the screen?

#include <iostream>

using namespace std;

int main()

{

int c = 5;

int *p = &c;

*p *= c;

cout << *(++p);

return 0;

}

I get 0 in Xcode, but it looks to me like it should be giving me the memory location. Please step me through the process.

Answer 1

Below is the answer with reference to image attached

Line 7: int c = 5;
we initialize variable c with value 5
Line 8 : int* p= &c;
p is an integer pointer it points to the address of variable of c
Line 9 : *p *= c;
This line actually means *p = *p * c which means multiplying value at address p with and storing it at address p
i.e storing (5*5 = 25 at p)
Line 10 : cout << *(++p);
since priority of () is greater than *, therefore ++p will take us to next address after p and *(++p) means printing the value
at ++p, which has currently no value so it will print a garbage value, which can be different everytime you run the code

Ouput for different runs

Thank you, please up vote.