Question

what is the output for the following code? explain the steps.

/*#include <iostream>

using namespace std;

int f(int &i)

{

i = 10;

return(5 * i);

}

int main()

{

int n = 5;

f(n);

cout << n << "\n";

return 0;

}

#include <iostream>

using namespace std;

int sub1(int n)

{

n--;

return n;

}

int main()

{

int m = 10;

for(int j = 0; j < 10; j++)

m -= sub1(j);

cout << m << "\n";

return 0;

}

#include <iostream>

using namespace std;

int myfunc(double);

int myfunc(float);

int main()

{

cout << myfunc(3.6) << "\n";

return 0;

}

int myfunc(double n)

{

return n * 2.0;

}

#include <iostream>

using namespace std;

int main()

{

int i = 1;

double x = 1.111;

cout << i << " " << x << "\n";

{

int x = 2;

double i = 2.222;

cout << i << " " << x << "\n";

}

return 0;

}

#include <iostream>

using namespace std;

int sum(int pt[], int n)

{

int temp = 0;

for (int i = 0; i < n; ++i)

{

temp += pt[i];

}

return temp;

}

int main()

{int i;

int total;

int pt[5];

for ( i = 0; i < 5; i++)

pt[i] = i;

total = sum(pt, 3);

cout << total << " " << i << endl;

return 0;

}

#include <iostream>

using namespace std;

int func ( string plant5, char plant4[])

{

for (char &x: plant5)

cin >> x;

}

int main()

{

char plant1[] = "Tree";

char plant2[] = {'T','R','E','E'};

cout << "i " << plant2[50] << endl;

char plant3[80] = "Tree";

char plant4[] = {'T','R','E','E','\0'};

string plant5 = "Tree";

cout << "i " << plant5[2];

func(plant5,plant4);

for (char x: plant5)

cout << x;

return 0;

}

*/

#include <iostream>

using namespace std;

double triangle(double base , double height = 10.0 ); //right

//double triangle(double base = 10.0, double height ); //wrong

int main()

{

cout << triangle(10.0) << "\n";

return 0;

}

double triangle(double base, double height)

{

return 0.5*base*height;

}

/*

#include <iostream>

using namespace std;

void what( int &a) // add const before int to fix the syntax error

{

cout << a;

}

int main()

{

const int whatVar = 1;

int b = 100;

what(whatVar);

cout << whatVar << " " << b;

}

I will a syntax error because if I pass a const

variable to a function I must add the const on the

function header.

*/

Answer 1

Dear Student ,

As per the requirement submitted above , kindly find the below solution.

Question 1:

Output :

Explanation :

• Here a method f is defined and parameter to this method is passed by reference.
• In the main on line 10 variable n=5 of integer type is declared.
• on line 11 method f is called and n is passed to method.
• But here parameter is passed as reference hence i will become 10 and 5*10=50 and return 50.
• but this return value is not stored in variable and on line 12 n is printed hence will get 10 as output.

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Question 2:

Output :

Explanation :

• Here method sub1() with n as parameter will decrement value of n by -1. and return n.
• In main method m=1 and for loop value of j will go from 0 to 9.
• When sub1(0) is called value of m becomes 11 because sub1(0) will return -1 and m=10-(-1) will be 11.
• like wise will get the value of j from 1 to 9 and finally will get -25.

*********************************

Question 3:

Output :

Explanation :

• Here myfun() is declared and from the main to this function 3.6 parameter is passed.
• and will get the result as 7.

*********************************

Question 4:

Output :

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Question 5:

Output :

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Question :

Output :

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Question :

Output :

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Question :

Output :

NOTE : PLEASE FEEL FREE TO PROVIDE FEEDBACK ABOUT THE SOLUTION.