a gaussian surface area of 0.005m^2 is placed between the plates of the capacitor at a 45 degree angle to the electric field. What is the electric flux through this surface? electric field value is 1.2x10^4 V/m. Thank you!
a gaussian surface area of 0.005m^2 is placed between the plates of the capacitor at a...
A dialectic material is inserted between the plates of a capacitor. The capacitor has an area of 0.02 m^2 and the plates are separated by 0.4 cm. If the dialectic constant is 2.6 a) Calculate the capacitance b) If the capacitor is connected across a 500 V source, find the change on it and the energy stored on it c) Find the value of electric field between the plates
and : No charur inside but there are charges outside the closed (TLC) Distinguishing between and : No producing an electric field. A cubie Gaussian surface with a side has two horizontal faces and is in a uniform electrie field of 30 N/C which is directed vertically upward. (1) Find the net electric flux through the cube. (Hint: If there are equal numbers of field lines going into and out of a CLOSED surface, the net flux through the surface...
A collection of 11 electrons and 4 protons are contained in a Gaussian (i.e., closed) surface. What is the total electric flux through the surface? 15 eleo 7 eleo 7 eleo 4 eleo Suppose a square surface of side 0.10 m is placed in a uniform electric field of magnitude 50.0 N/C. If the angle between the field and the normal to the surface is 25.0°, what is the magnitude of the electric flux through the surface? 4.5 N-m2/ 0.45...
The potential difference between the plates of a parallel plate capacitor is 45 V and the electric field between the plates has a strength of 850 V/m. If the plate area is 4.0
Consider an ideal parallel plate capacitor, having vacuum between two plates of area A and separation d. The shape of the plates is arbitrary. By the following steps, prove that the capacitance is 0 d where ε0 is the permittivity. Assume that the charge on each plate is electric field E between the plates is uniform. , and that the Use Gauss' law to calculate the electric field E between the plates in terms of Q and A. (Use a...
2. Consider a capacitor created when two identical conducting plates are placed parallel and close to each in other in vacuum The surface area for each plate is e.0400 m2. The two plates are separated by a distance of e.00200 m. When an electric potential difference of 5e.e v is established between the two plates, what is the magnitude of the electrostatic force between the charged plates? Is the force attractive or repulsive? 3. What mass on the Earth surface...
An air-filled parallel-plate capacitor has plates of area 2.70 cm2 separated by 0.50 mm. The capacitor is connected to a 6.0-V battery. (a) Find the value of its capacitance. ________ pF (b) What is the charge on the capacitor? ________ pC (c) What is the magnitude of the uniform electric field between the plates? ________ V/m
A parallel-plate capacitor has capacitance C0 = 7.00 pF when there is air between the plates. The separation between the plates is 1.10 mm. a. What is the maximum magnitude of charge Q that can be placed on each plate if the electric field in the region between the plates is not to exceed 3.00 x 104 V/m? b. A dielectric with K = 2.60 is inserted between the plates of the capacitor, completely filling the volume between the plates. Now...
An air-filled parallel-plate capacitor has plates of area 2.80 cm^2 separated by 2.50 mm. The capacitor is connected to a(n) 17.0 V battery. Find the value of its capacitance. _____ pF What is the charge on the capacitor? ______ pC What is the magnitude of the uniform electric field between the plates ___________ N/C
A parallel-plate capacitor has capacitanceC0 = 7.80 pF when there is air between the plates. The separation between the plates is 1.10 mm . What is the maximum magnitude of charge that can be placed on each plate if the electric field in the region between the plates is not to exceed 3.00×104 V/m ? A dielectric with K = 2.80 is inserted between the plates of the capacitor, completely filling the volume between the plates. Now what is the...