Question

A collection of 11 electrons and 4 protons are contained in a Gaussian (i.e., closed) surface. What is the total electric flux through the surface? 15 eleo 7 eleo 7 eleo 4 eleo Suppose a square surface of side 0.10 m is placed in a uniform electric field of magnitude 50.0 N/C. If the angle between the field and the normal to the surface is 25.0°, what is the magnitude of the electric flux through the surface? 4.5 N-m2/ 0.45 N-m2/c o.50 N-m2/o 0.21 N.m2/c

Answer 1

Net charge enclosed by the Gaussian sphere = q_en = (4 - 11) times 1.6 times 10^-19 C q_en = -7 times e = -(1.12 times 10^-18) C Now, total electric flux passing through the Gaussian surface = phi = q_en/e_0 = -7e/e_0, where e_0 = 8.854 times 10^-12 C^2 N^-1 m^2 = > phi = q_en/e_0 = -(1.12 times 10^-18)/8.854 times 10^-12 NC^-1 m^2 = -(1.26496499 times 10^-7) NC^-1 m^2 so option (B) is correct.