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14. The reaction 2 H2(g) + 2 NO(g) ® N2(g) + 2 H2O(g) is proposed to...

14. The reaction 2 H2(g) + 2 NO(g) ® N2(g) + 2 H2O(g) is proposed to have the alternate mechanism:

2 NO(g) ® N2O2(g)                               FAST

N2O2(g) + H2(g) ® N2O(g) + H2O(g)       SLOW

N2O(g) + H2(g) ® N2(g) + H2O(g)           FAST

If the rate law is found to be Rate = k[H2][NO]2, could this support the proposed mechanism? Does the rate law indicate that the reaction is termolecular?

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The rate law for the reaction is given by the slowest step of reaction mechanism. Here the slowest step is the second step of the reaction , where N2O2 and H2 are the reactants. Since N2O2 is the intermediate that is formed in the step 1 of the reaction , so it will be replaced by NO.

So the rate law will be : Rate = k[H2] [NO]2

This rate law correctly supports the proposed mechanism.

The order of H2 in the rate law is 1 and that of NO is 2 , so the overall order of reaction = 1 + 2 = 3. This indicates that the reaction is termolecular.

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