14. The reaction 2 H2(g) + 2 NO(g) ® N2(g) + 2 H2O(g) is proposed to have the alternate mechanism:
2 NO(g) ® N2O2(g) FAST
N2O2(g) + H2(g) ® N2O(g) + H2O(g) SLOW
N2O(g) + H2(g) ® N2(g) + H2O(g) FAST
If the rate law is found to be Rate = k[H2][NO]2, could this support the proposed mechanism? Does the rate law indicate that the reaction is termolecular?
Ans :
The rate law for the reaction is given by the slowest step of reaction mechanism. Here the slowest step is the second step of the reaction , where N2O2 and H2 are the reactants. Since N2O2 is the intermediate that is formed in the step 1 of the reaction , so it will be replaced by NO.
So the rate law will be : Rate = k[H2] [NO]2
This rate law correctly supports the proposed mechanism.
The order of H2 in the rate law is 1 and that of NO is 2 , so the overall order of reaction = 1 + 2 = 3. This indicates that the reaction is termolecular.
14. The reaction 2 H2(g) + 2 NO(g) ® N2(g) + 2 H2O(g) is proposed to...
QUESTION 9 A proposed mechanism for the reaction 2NO(g) +2H2(g) → N2(g) + 2H2O(g): Step 1: 2NO(g) → N2O2(g) (very fast, reversible) Step 2: N2O2(g) + H2(g) → N2O(g) + H2O(g) (slow) Step 3: N2O(g) + H2(g) →N2(g) + H2O(g) (fast) What is the rate law for the overall reaction? k[N2O][H2] k[NO]2[H2] k[NO]2[H2]2 k[NO]1/2[H2] k[NO]2
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