A sample of 40 statistics exam showed a mean grade of 92.67 with a standarddeviation of...
A sample of 40 statistics exam showed a mean grade of 92.67 with a standarddeviation of 1.79. Using significance level of 5%, determine whether there is sufficient evidenceto support the claim that the new information is different from 92.84 using p-value approach.
Homework Answers
This is the two tailed test .
The null and alternative hypothesis is
H0 : 
= 92.84
Ha :
92.84
Test statistic = t
= (
- 
) / s / 
n
= (92.67 - 92.84) / 1.79 /
40
Test statistic = -0.6006
df = 39
P-value = 0.5515
= 0.05
P-value >
Fail to reject the null hypothesis .
There is sufficient evidence to conclude that the
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A sample of 40 statistics exam showed a mean grade of 92.67 with
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