a). how many cycles are there in 1 second of the signal x(t)= cos(2pi100t) ? b)....
(a) The signal x(t) 3 cos (2n404 t + π/4) + cos(2n660t-n/5) is sampled at 20kHz. How many samples would be stored after 60 ms? (b) If x(t) = 4 cos(2π250t + 2n/7), what is the period of this signal? (c) For CDs, the sampling rate is 44,100 samples per second. How often (in seconds) must the ADC sample the signal? (a) The signal x(t) 3 cos (2n404 t + π/4) + cos(2n660t-n/5) is sampled at 20kHz. How many samples...
2. Consider the signal f(t) = 20 cos(5t) + cos(9t) sin(5t) - 7 (a) What is the highest angular frequency present in this signal? What is the highest numerical frequency present in this signal? (b) What is the Nyquist frequency? rate for this signal? Did you use the angular or the numerical (c) If you sample this signal with sampling period T, which values of T may you choose to be in accordance with the Nyquist rate? Choose and fix...
Problem 4.(30 pts) Given the analog signal x(t) cos(2 cos(3t)+2 sin(4mt) A.(10 pts) Find the Nyquist frequency (sampling frequency) which guarantees That x() can be recovered from it's sampled version xIn] with no aliasing. B.(10 pts) If the sampling period of Ts 0.4 see is used identify all discrete frequencies Of the signal x(t), also indicate if this sampling period is adequate to recover x(t) from xn] C.(10 pts) Suppose signal x(t) is modulated by signal e(t) = cos(2000mt) what...
Question 10 6.25 pts A continuous-time signal is given by X(t) = cos(27[C]t) + sin(27[C]t) where C=6.24 Rewrite x(t) as X(t) = A cos(wt + o) where -1 << Enter the value of the fundamental period T in seconds; Enter your answer with three decimal places accuracy.
1. A signal, x(t) = 2 cos(21fmt), is applied to the ideal sampling circuit in the Figure below (left) where fm = 1 kHz. A sampling function, p(t), whose characteristic is given in the Figure below (right), is used when Ts = 0.25 ms. a) (5p) Plot the sampled signal, xs(t), in time domain for at least one period. b) [10p] Express the Fourier transform of sampled signal, xs(t), denoted by Xs , in frequency domain. c) [10p] Plot the...
1. Given a baseband signal m(t) sin(1000mt) cos(3000nt) + cos(3700nt a. Sketch the spectrum of m(t) (Hint. sin(a) cos(b) 0.5 sin(a +b) +0.5sin a-b)) b. Sketch the spectrum of DSB-CS signal m(t)cos(10000mt) C ldentify the upper sideband {USB) and lower sideband (LSB) spectra d. Give the black diagram of the receiver to receive DSB-CS signal in (b). 2. baseband signal m(r)--0.5 + Σ..小(t-n)-u(t-0.5-n)] where ult) is the Given unit step function, an amplitude modulated signal is as SAM 107+ m(0cos...
solve using scilab show codes Task 1 Generate a time vector (series) “t' which contains the number 0 to 9. i.e 0 st 10 with a step size of 1 Repeat the experiment with a step size of 0.01. (1.5 marks) 57%, 13:23 Task 2.2 Let X(t) = A sin(217ft) where A= Amplitude Frequency E-Time a) Create the signals X (t) = A, sin(26ft) and X (t) = A, sin(271f_t) where A, = 2, A, = 4, f = 20,...
10. Find the Fourier transform of a continuous-time signal x(t) = 10e Su(t). Plot the magnitude spectrum and the phase spectrum. If the signal is going to be sampled, what should be the minimum sampling frequency so that the aliasing error is less than 0.1 % of the maximum original magnitude at half the sampling frequency. 11. A signal x(t) = 5cos(2nt + 1/6) is sampled at every 0.2 seconds. Find the sequence obtained over the interval 0 st 3...
ints) A continuous time signal is given below: x(t) = 10 + 3 sin (20t + 3) + 5 cos(40π) This is sampled at t = 0.01 n to get a the discrete-time signal x[n], which is then applied to an ideal DAC to obtain a reconstructed continuous time signal y(t). a. i. Determine x[n] and graph its samples, using Matlab, along with the signal x(t) in one plot, plot a few cycles of x(t). ii. Determine the reconstructed signal,...
Q4. For each signal, if it is periodic, find the fundamental period T. (in seconds) and the fundamental frequency (in rad/s). Otherwise prove that the signal is not periodic. [1 + 1 - 2 marks) a) X(t) = cos(5t) + sin(25t) b)x() = sin 91 + + sin(61 - 7) + cos(391)