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Twenty-two stoke patients performed a maze task. The mean number of trials for success was 14.7...

Twenty-two stoke patients performed a maze task. The mean number of trials for success was 14.7 with a standard deviation of 6.2. If the population mean for this task is 6.5… a. What is the tcv for a two-tailed test with alpha set at .05? tcv

b. What is the t-statistic? t =

c. Is this a statistically significant finding? ☐Yes ☐No

d. What is the effect size? d = ;

e. What can you conclude from this result?

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Answer #1

The hypothese are:

a) The critical value t0.05,21 =2.08 which is calculated using T table shown below at degree of freedom, DF=n-1=22-1=21

b) The test statistic:

c) Decision:

SInce T >>t hence we reject the null hypothesis.and conclude that there is enough evidence to support the claim.

d) The effect size is calculated using

e) from the effect size calculation we can conclude that there is enough significance to support the claim because it has a large effect.

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