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An equilateral triangle has sides that are 6 cm long. What is the probability that a...

An equilateral triangle has sides that are 6 cm long. What is the probability that a point chosen at random in the triangle is within 1 cm of a corner?

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Answer #1

P[ a point chosen at random in the triangle is within 1 cm of a corner ] = Area within 1 cm of a corner / Area of triangle

Area of equilateral triangle of side a =

For a = 6

Area of triangle =

Area of triangle =

Area of triangle = 15.59

Area within 1 cm of a corner = 3*area of sector with angle 60 and radius 1 cm

Area within 1 cm of a corner =

Area within 1 cm of a corner =

Area within 1 cm of a corner = 3.14

P[ a point chosen at random in the triangle is within 1 cm of a corner ] = 3.14/15.59

P[ a point chosen at random in the triangle is within 1 cm of a corner ] = 0.2014

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