Consider the following discrete probability distribution along with observed frequencies for each day of the week. Complete parts a and b below.
Weekday Monday Tuesday Wednesday Thursday Friday Total
Probability 0.10 0.20 0.05 0.30 0.35 1.00
Observed Frequency, f Subscript o 12 26 9 39 44 130
a. Perform a chi-square test using alphaequals0.05 to determine if the observed frequencies follow a discrete probability distribution. Determine the null and alternative hypotheses. Choose the correct answer below.
A. Upper H 0: The distribution of the variable differs from the normal distribution. Upper H 1: The distribution of the variable is the normal distribution.
B. Upper H 0: The distribution of the variable is the same as the given distribution. Upper H 1: The distribution of the variable differs from the given distribution.
C. Upper H 0: The expected frequencies are all equal to 5. Upper H 1: At least one expected frequency differs from 5. D. Upper H 0: The distribution of the variable differs from the given distribution. Upper H 1: The distribution of the variable is the same as the given distribution.
Compute the value of the test statistic. (Round to two decimal places as needed.)
Identify the critical value. T(Round to two decimal places as needed.)
Does the data provide sufficient evidence that the distribution of the variable differs from the given distribution?
A. Yes, because there is sufficient evidence to reject the null hypothesis.
B. No, because there is not sufficient evidence to reject the null hypothesis.
C. No, because there is sufficient evidence to reject the null hypothesis.
D. Yes, because there is not sufficient evidence to reject the null hypothesis.
b. Determine the p-value and interpret its meaning. p-valuee (Round to three decimal places as needed.)
Interpret the p-value. The p-value is the probability of observing a test statistic (greater than/ equal to/ less than) the part a statistic, assuming (the distribution of the variable differs from the given distribution/ at least one expected frequency differs from 5/ the expected frequencies are all equal to 5/ the distribution of the variable differs from the normal distribution/ the distribution of the variable is the normal distribution/ the distribution of the variable is the same as the given distribution)
a)
option B is correct
B. Upper H 0: The distribution of the variable is the same as the given distribution. Upper H 1: The distribution of the variable differs from the given distribution.
applying chi square goodness of fit test: |
relative | observed | Expected | residual | Chi square | |
category | frequency(p) | Oi | Ei=total*p | R2i=(Oi-Ei)/√Ei | R2i=(Oi-Ei)2/Ei |
1 | 0.1000 | 12.0 | 13.00 | -0.28 | 0.077 |
2 | 0.2000 | 26.0 | 26.00 | 0.00 | 0.000 |
3 | 0.0500 | 9.0 | 6.50 | 0.98 | 0.962 |
4 | 0.3000 | 39.0 | 39.00 | 0.00 | 0.000 |
5 | 0.3500 | 44.0 | 45.50 | -0.22 | 0.049 |
total | 1.000 | 130 | 130 | 1.0879 | |
test statistic X2 = | 1.09 |
for 0.05 level and 4 df :crtiical value X2 = | 9.49 |
B. No, because there is not sufficient evidence to reject the null hypothesis.
b)
p value =0.896
The p-value is the probability of observing a test statistic greater than the part a statistic, assuming the distribution of the variable is the same as the given distribution
Consider the following discrete probability distribution along with observed frequencies for each day of the week....
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