Question

Here is the problem:

PCl3(g) + Cl2(g) <==> PCl5(g) Kc = 26 at 275K
all in a 6.40 L flask
PCl3: .1 mol

Cl2: .1 mol

PCl5: .01 mol

Assuming ideal gas conditions, What is the Kp, Qp, and the shift of direction?  (if someone can help me set up this problem that would be great!)

Answer 1

where

Now assuming ideal behavior of PCl₃ , Cl₂ and PCl_{5 ,} we can calculate their individual partial pressures as,

Given,

Hence,

Now. we can calculate Q_p (which is reaction quotient in terms of pressure),

From above analysis, it is clear that K_p > Q_p which indicates that the net reaction proceeds to right direction i.e. the shift of direction towards the right side of the reaction.