Colorblindness is a sex-linked X-linked recessive trait. A normal woman marries a color-blind man. They have a color-blind daughter. What are the genotypes of all three people?
Answer
Colorblindness is a sex linked X linked recessive trait.
For female to be colorblind then both the X chromosomes has to carry color blind allele. Normal female can be carrier too means only one X chromosome carries color blind allele.
For male to be colorblind, only one color blind allele is sufficient to have color blind male.
C (capital) : color blind allele and c (small) is normal allele
Gentotype of female: XcXC (C is color blind allele and c is normal allele)
Genotype of male: XCY (Y chromosome does not carry color blind allele means only one colorblind allele is sufficient to have color blind male).
Genotype of colorblind daughter : XCXC (Both X chromosome has to carry for female to be color blind)
Female genotype (XcXC): Gametes: Xc or XC
Male genotype (XCY) : Gametes: XC or Y
Xc | XC | |
XC | XcXC (carrier female) | XCXC (color blind female) |
Y | XcY (Normal male) | XCY (Color blind male) |
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