Question

By using C++, write a program and show the program output that convert any hexadecimal expansion to:

i) binary expansion,

ii) octal expansion, and

iii) decimal expansion.

Answer 1

`Hey,

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#include<iostream>
#include<string.h>
using namespace std;
void decToBinary(int n)
{
// array to store binary number
int binaryNum[32];
  
// counter for binary array
int i = 0;
while (n > 0) {
  
// storing remainder in binary array
binaryNum[i] = n % 2;
n = n / 2;
i++;
}
cout<<"Binary is ";
// printing binary array in reverse order
for (int j = i - 1; j >= 0; j--)
cout << binaryNum[j];
cout<<endl;
}
void decToOctal(int n)
{
  
// array to store octal number
int octalNum[100];
  
// counter for octal number array
int i = 0;
while (n != 0) {
  
// storing remainder in octal array
octalNum[i] = n % 8;
n = n / 8;
i++;
}
cout<<"Octal is ";
// printing octal number array in reverse order
for (int j = i - 1; j >= 0; j--)
cout << octalNum[j];
cout<<endl;
}
// Function to convert hexadecimal to decimal
int hexadecimalToDecimal(char hexVal[])
{
int len = strlen(hexVal);
  
// Initializing base value to 1, i.e 16^0
int base = 1;
  
int dec_val = 0;
  
// Extracting characters as digits from last character
for (int i=len-1; i>=0; i--)
{
// if character lies in '0'-'9', converting
// it to integral 0-9 by subtracting 48 from
// ASCII value.
if (hexVal[i]>='0' && hexVal[i]<='9')
{
dec_val += (hexVal[i] - 48)*base;
  
// incrementing base by power
base = base * 16;
}
  
// if character lies in 'A'-'F' , converting
// it to integral 10 - 15 by subtracting 55
// from ASCII value
else if (hexVal[i]>='A' && hexVal[i]<='F')
{
dec_val += (hexVal[i] - 55)*base;
  
// incrementing base by power
base = base*16;
}
}
  
return dec_val;
}
  
// Driver program to test above function
int main()
{
char hexNum[] = "1A";   
int dec=hexadecimalToDecimal(hexNum);
decToBinary(dec);
decToOctal(dec);
cout << "Decimal is "<<dec<< endl;
  
  
return 0;
}

Kindly revert for any queries

Thanks.