given n(E')=x and P(E)=y/(x+y), find n(S), n(E), P(E), odds (E).
Please also explain the methods behind doing so. Thank you so much!!!
P(E) = y/(x+y)
P(E') = 1-P(E) = x/(x+y)
as n(E') = x hence n(S) = x+y
P(E) = n(E)/n(S) hence n(E) = y
P(E)=y/(x+y)
P(E') = x/(x+y)
odds (E) is y:x
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given n(E')=x and P(E)=y/(x+y), find n(S), n(E), P(E), odds (E). Please also explain the methods behind...
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