When excess Cl2 at constant pressure reacts with 0.300 mol of CH4(g) 295 kJ of energy evolves. Calculate the value of ΔH for this reaction, as written.
CH4(g) + Cl2(g) → CHCl3(l) + H2(g) ΔH = ?
a) -1970 kJ
b) -1770 kJ
c) +1970 kJ
d) -983 kJ
e) +1770 kJ
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When excess Cl2 at constant pressure reacts with 0.300 mol of CH4(g) 295 kJ of energy...
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