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When excess Cl2 at constant pressure reacts with 0.300 mol of CH4(g) 295 kJ of energy...

When excess Cl2 at constant pressure reacts with 0.300 mol of CH4(g) 295 kJ of energy evolves. Calculate the value of ΔH for this reaction, as written.

CH4(g) + Cl2(g) → CHCl3(l) + H2(g)        ΔH = ?

a) -1970 kJ

b) -1770 kJ

c) +1970 kJ

d) -983 kJ

e) +1770 kJ

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