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A 0.190 kg plastic ball moves with a velocity of 0.30 m/s. It collides with a...

A 0.190 kg plastic ball moves with a velocity of 0.30 m/s. It collides with a second plastic ball of mass 0.107 kg, which is moving along the same line at a speed of 0.10 m/s. After the collision, both balls continue moving in the same, original direction, and the speed of the 0.107 kg ball is 0.26 m/s. What is the new velocity of the first ball?

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Answer #1

m1 v1i + m2 v2i = m1 v1f + m2 v2f

m1 v1f = m1 v1i + m2 v2i - m2 v2f

v1f = [m1 v1i + m2 v2i - m2 v2f] / m1

= [(0.19 * 0.30) + (0.107 * 0.1) - (0.107 * 0.26)] / [0.190]

new velocity of the first ball = 0.209 m/s

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